All categories

3 years ago

2 and 5. What is the LCM?

1 answer:

5 0

Well, first of all, LCM means Lowest Common Multiple. So you have to write out the factors of each of the numbers. So that will be;
2= 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
5=5, 10, 15, 20
So now, you have to pick out the numbers that are common to both numbers. So;
10, 20
10 and 20 are the only common numbers. So you have to look for the lowest common number. And that is 10. So the LCM is 10.. Hope i helped. Have a nice day.

You might be interested in

Solve the proportion 3/2 = 4/x-2? plzzzzz someone hellllppppp

Ronch [10]

Answer:

$\frac{3}{2}=\frac{4}{x-2}\\ \\3(x-2)=2*4\\\\3x-6=8\\\\3x=8+6\\\\3x=14\\\\x=14/3\\\\x=4\frac{2}{3}$

4 0

3 years ago

Negative 12 plus 44 negative 19 plus 61

antiseptic1488 [7]

Your answer would be 74 if you are looking for the answer.

8 0

4 years ago

Read 2 more answers

Juan needs to take an Uber to get to the movies. The Uber charges $1.50 for the first mile, and then $1.55 for each mile after t

nordsb [41]

Answer: 5.8 miles

Step-by-step explanation:

10.49 - 1.5 = 8.99

8.99 / 1.55 = 8.99

7 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

3 years ago

Please help (speed practice)

igomit [66]

Answer:

3.5hrs

Step-by-step explanation:

Speed=80km/hr

distance=400km

time=x

time=distance

speed

time=400km

80km/hr

T=5hrs

6 0

3 years ago

Read 2 more answers