Answer:
Q = 1.404 × 10^(5) KJ
Explanation:
We are given:
Mass;m = 500 g = 0.5kg
Temperature 1;T1 = 28 °C
Temperature:T2 = 150 °C
Specific heat capacity;c_p = 4183 J/Kg °C
Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.
The heat energy needed is given by;
Q = sensible heat energy + Latent heat
Formula for sensible heat is;
Sensible heat energy = mc(t2 - t1)
Formula for Latent heat is ;
Latent heat = mL
Thus:
Q = mc(t2 - t1) + mL
Q = m[c(t2 - t1) + L]
Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))
Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ
For this case we have that by definition, physical power refers to the amount of work done for a unit of time.
So:
Where:
W: It's the work
t: It's time
The power units are in 
So, according to the problem data we have:
Clearing the work of the formula:
Thus, the work is 1200 joules.
Answer:
Option C
The branch of mechanics which deals with the motion of an object without considering the cause of motion, is known as Kinematics ~
I hope it helps ~
Answer:
Explanation:
Given data:
Rotating cylinder length = 9 mi
diameter of cylinder is 5.9 mi
we know that linear acceleration is given as
a = r ω^2
where ω is angular velocity
so
Answer:
37.125 m
Explanation:
Using the equation of motion
s=ut+0.5at^{2} where s is distance, u is initial velocity, t is time and a is acceleration
<u>Distance during acceleration</u>
Acceleration, a=\frac {V_{final}-V_{initial}}{t} where V_{final} is final velocity and V_{initial} is initial velocity.
Substituting 0.0 m/s for initial velocity and 4.5 m/s for final velocity, acceleration will be
a=\frac {4.5 m/s-0 m/s}{4.5 s}=1 m/s^{2}
Then substituting u for 0 m/s, t for 4.5 s and a for 1 m/s^{2} into the equation of motion
s=0*4.5+ 0.5*1*4.5^{2}=0+10.125
=10.125 m
<u>Distance at a constant speed</u>
At a constant speed, there's no acceleration and since speed=distance/time then distance is speed*time
Distance=4.5 m/s*6 s=27 m
<u>Total distance</u>
Total=27+10.125=37.125 m
