Answer:
panic anxiety
Explanation:
Panic anxiety occur unexpectedly, sometimes even when waking up from sleep characterized by its unexpectedness and debilitating, immobilizing intensity it is caused by Severe stress, such as the death of a loved one, divorce, or job loss can also trigger panic anxiety. Panic attacks can also be caused by medical conditions and other physical cause e.g sitting in a position for hours under an unfavorable condition doing a recurring activity. Panic anxiety may occur as part of another disorder, such as panic disorder, social phobia, or depression. Regardless of the cause, panic attacks are treatable.
Answer:
<em>At 574.59 Kelvin, the Fahrenheit temperature will be 574.59 °F.</em>
Explanation:
We first need to find a relation between the Kelvin scale and the Fahranheit scale. We'll use the Celsius scale to relate them.
The Kelvin and Celsius scales are related by the formula:
K = °C + 273.15
Solving for °C:
°C = K - 273.15
Besides, the Kelvin and Celsius scales are related by:
°C = 5 ⁄ 9(°F - 32)
Now we find a temperature, say X, where both scales coincide. Equating both formulas:
X - 273.15=5 ⁄ 9(X - 32)
Multiply by 9:
9X - 2,458.35 = 5X - 160
Simplifying:
4X = 2,458.35 - 160=2,298.35
Solving:
X =2,298.35 / 4 = 574.59
At 574.59 Kelvin, the Fahrenheit temperature will be 574.59 °F.
Kinetic energy is the energy possessed by an object when that object is moving in space. The higher the mass of an object or higher the speed of an object the higher the kinetic energy will be.
So to calculate the Kinetic Energy we can use the following formula
K.E=(1/2)*m*v^2
Inserting the values in formula gives:
K.E=1/2*7.26*2^2
14.52J
This is the final answer which gives the kinetic energy of the ball.
The answer should be C. Both matter and energy because physical sciences are sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects.
Matter and energy fall in with chemistry
Answer:
The maximum energy stored in the combination is 0.0466Joules
Explanation:
The question is incomplete. Here is the complete question.
Three capacitors C1-11.7 μF, C2 21.0 μF, and C3 = 28.8 μF are connected in series. To avoid breakdown of the capacitors, the maximum potential difference to which any of them can be individually charged is 125 V. Determine the maximum energy stored in the series combination.
Energy stored in a capacitor is expressed as E = 1/2CtV² where
Ct is the total effective capacitance
V is the supply voltage
Since the capacitors are connected in series.
1/Ct = 1/C1+1/C2+1/C3
Given C1 = 11.7 μF, C2 = 21.0 μF, and C3 = 28.8 μF
1/Ct = 1/11.7 + 1/21.0 + 1/28.8
1/Ct = 0.0855+0.0476+0.0347
1/Ct = 0.1678
Ct = 1/0.1678
Ct = 5.96μF
Ct = 5.96×10^-6F
Since V = 125V
E = 1/2(5.96×10^-6)(125)²
E = 0.0466Joules
