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Daniel [21]
3 years ago
11

Please help me i dont understand it This subject is Earth science

Physics
1 answer:
Anton [14]3 years ago
6 0
Here are your answers

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3
kramer

Answer:

60.2 J

Explanation:

Efficiency is the ratio of work out to work in.

e = Wout / Win

0.86 = Wout / 70 J

Wout = 60.2 J

5 0
3 years ago
Read 2 more answers
a skier starts from rest and skis down a 82 meter tall hill labeled h1, into a valley and staught back up another 35 meter hill(
horrorfan [7]

Answer:

She is going at 30.4 m/s at the top of the 35-meter hill.    

Explanation:

We can find the velocity of the skier by energy conservation:

E_{1} = E_{2}

On the top of the hill 1 (h₁), she has only potential energy since she starts from rest. Now, on the top of the hill 2 (h₂), she has potential energy and kinetic energy.

mgh_{1} = mgh_{2} + \frac{1}{2}mv_{2}^{2}    (1)

Where:

m: is the mass of the skier

h₁: is the height 1 = 82 m

h₂: is the height 2 = 35 m

g: is the acceleration due to gravity = 9.81 m/s²  

v₂: is the speed of the skier at the top of h₂ =?

Now, by solving equation (1) for v₂ we have:

v_{2}^{2} = \frac{2mg(h_{1} - h_{2})}{m}  

v_{2} = \sqrt{2g(h_{1} - h_{2})} = \sqrt{2*9.81 m/s^{2}*(82 m - 35 m)} = 30.4 m/s    

Therefore, she is going at 30.4 m/s at the top of the 35-meter hill.

I hope it helps you!  

6 0
3 years ago
What is the sum of 231 + 5080 + 80 + 13 + 9​
Gemiola [76]

Answer:

5413

Explanation:

add them up

6 0
3 years ago
A car starts from rest with an acceleration of 8 m/s/s for a time of 4 s. What was the car's final velocity?
Aleks [24]
32m/s
8m/s x 4s= 32m/s
6 0
2 years ago
According to Newton's third law of motion, if you push against a wall, the wall will __________.
beks73 [17]
It would be C as the law says "<span>Formally stated, </span>Newton's third law<span> is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object."</span>
8 0
3 years ago
Read 2 more answers
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