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2 years ago

A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of

Physics

1 answer:

a_sh-v [17]2 years ago

8 0

Answer:

16m/s

Explanation:

Mv=mv

5000x8=2500x v

V=5000x8/2500

V=40000/2500

= 16m/s

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If the range of a projectile's trajectory is ten times larger than the height of the trajectory, then what was the angle of laun

Lunna [17]

Answer:

Angle of projection from the horizontal will be $21.80^{\circ}$

Explanation:

We have given that range of the projectile is 10 times the height of the projectile

Let the projectile is projected with velocity u at an angle $\Theta$

Range of the projectile is equal to $R=\frac{u^2sin2\Theta }{g}$

And height of the projectile is equal to $h=\frac{u^2sin^2\Theta }{2g}$

Now according to question range is 10 times of height

So $\frac{u^2sin2\Theta }{g}=10\times \frac{u^2sin^2\Theta }{2g}$

$sin2\Theta =5sin^2\Theta$

$2sin\Theta cos\Theta =5sin^2\Theta$

$tan\Theta =\frac{2}{5}=0.4$

$\Theta =tan^{-1}0.4=21.80^{\circ}$

So angle of projection from the horizontal will be $21.80^{\circ}$

3 0

3 years ago

If the strings have the same thickness butdifferent lengths, which of the following parameters, if any, willbe different in the

gizmo_the_mogwai [7]

Answer:

1.Length is one of the four factors on which the wave frequency depends. So if the length of the string changes then there will be a change in the vibration of string. So in this case if the lengths are different then the wave frequency of both will be different.

2. Wave speed will be the same as it depends on tension and linear density of it.

3. Wavelength itself is find out by the length of string so it depends on length and it will vary with the lengths of strings.

Explanation:

7 0

3 years ago

A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from i

murzikaleks [220]

Answer:

f" = 40779.61 Hz

Explanation:

From the question, we see that the bat is the source of the sound wave and is initially at rest and the object is in motion as the observer, thus;

from the Doppler effect equation, we can calculate the initial observed frequency as:

f' = f(1 - (v_o/v))

We are given;

f = 46.2 kHz = 46200 Hz

v_o = 21.8 m/s

v is speed of sound = 343 m/s

Thus;

f' = 46200(1 - (21/343))

f' = 43371.4285 Hz

In the second stage, we see that the bat is now a stationary observer while the object is now the moving source;

Thus, from doppler effect again but this time with the source going away from the obsever, the new observed frequency is;

f" = f'/(1 + (v_o/v))

f" = 43371.4285/(1 + (21.8/343))

f" = 40779.61 Hz

4 0

2 years ago

Suppose the coefficient of kinetic friction between mA and the plane in the figure(Figure 1) is μk = 0.15, and that mA=mB=2.7kg.

luda_lava [24]

A )
T = mB g + mB a
T + mA a - mA g sin 35° = (Mi) mA g cos 35°
------------------------------------------------------------
T = 2.7 · 9.81 + 2.7 a
T = 26.487 + 2.7 a
26.487 + 2.7 a + 2.7 a - 2.7 · 9.81 · 0.574 = 0.15 · 2.7 · 9.81 · 0.819
5.4 a + 26.487 - 15.2023 = 3.2539
5.4 a = 8.0296
a = 1.487 ≈ 1.5 m/s²
B )
T = 2,7 · 9.81 = 26.487
26.487 - 15.2035 = (Mi) · 2.7 · 9.81 · 0.819
11.2835 = (Mi) · 21.69
(Mi) = 11.2835 : 21.69 = 0.52

4 0

3 years ago

Reading glasses use what property of light waves

tresset_1 [31]

Visible range of electromagnetic radiation

5 0

2 years ago