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sattari [20]
3 years ago
13

Can someone help with this, or just give a example of one???

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0
Really simple, just do what they tell you to

example 10
1.divide y by 7
so 7/y
2. then add x

7/y+x
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I answered it but I just need someone to answer just to make sure mine are right
Artemon [7]
<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

Learn more here:

brainly.com/question/2944195

5 0
2 years ago
Find the derivative of the function y = sin(tan 4x)
Virty [35]
\bf y=sin[tan(4x)]\implies \cfrac{dy}{dx}=\stackrel{chain~rule}{cos[tan(4x)]\cdot sec^2(4x)\cdot 4}&#10;\\\\\\&#10;\cfrac{dy}{dx}=4cos[tan(4x)]sec^2(4x)
4 0
2 years ago
I need help with this question and it’s very urgent!!!!
andreev551 [17]

Answer:

AAS

Step-by-step explanation:

8 0
2 years ago
Please answer below if you know it! I am desperate
sveta [45]
A line of symmetry basically is like a reflection of a shape, so your answer is D.
5 0
3 years ago
Two intersecting segments form the diagonals of a quadrilateral. What additional information do you need to
Aleksandr-060686 [28]

Answer:

B. They must bisect each other

Step-by-step explanation:

Found the answer on quizziz

7 0
3 years ago
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