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3 years ago

What is the standard form of the following equation? y = −25x + 4

Mathematics

1 answer:

spayn [35]3 years ago

5 0

Answer: y+0.16=x

Step-by-step explanation:

You will need to add 4 to other side to get 25x alone then divide by 25 and get your answer

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There are two rectangles Jared is examining. He knows the width of the first rectangle measures

egoroff_w [7]

1st rectangle:

width: 2.48cm

length: 4.96

2nd rectangle:

width: 4.96 (equals to the length of the 1st rectangle)

area: 9.92

length: 9.92/4.96 = 2

3 0

3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

What is the area of this polygon?

Cerrena [4.2K]

Answer:

<h2>39 units</h2>

Solution,

Total area=Area of ABCD+ Area of triangle ADE

 $(ab \times bc) + \frac{1}{2} \times ad \times ef \\ = (5 \times 6) + \frac{1}{2} \times 6 \times 3 \\ = 30 + 9 \\ = 39 \: {units}^{2}$ 

hope this helps...

Good luck on your assignment...

7 0

3 years ago

Convert 1.43 g/mL to the unit g/m3.

viktelen [127]

1430000 is the answer to Converting 1.43 g/mL to the unit g/m3 Also, 1 ml = 1cm3 = 1E-6 m3 
1.43/ml= 1.43E-6 g/m3 (1.43 x 10-6 g/m3) and 1.43 x 106 (grams / cubic meter) =0.15158 kg / m3

8 0

3 years ago

HELP PICTURE IS SHOWN

scoray [572]

The answer is letteer C. You just have to multiply 9 and pi

8 0

3 years ago

Read 2 more answers