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Serggg [28]
4 years ago
6

Elements from group/column ______ will ionically bond with halogens in a 1 to 1 ratio. A) 1 (or 1A) B) 2 (or 2A) Eliminate C) 3

(or 3A) D) 17 (or 7A)
Chemistry
2 answers:
ludmilkaskok [199]4 years ago
7 0

Elements from group/column ______ will ionically bond with halogens in a 1 to 1 ratio.

ANSWER A) 1 (or 1A)

(Example: Sodium (Na) is from group 1 and will ionically bond with chlorine (Cl), a halogen, to form salt (NaCl) in a 1 to 1 ratio.

Dovator [93]4 years ago
3 0

A) 1( or 1A). This is the answer to the question.

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The top of a wave is called the wave crest.

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At 25 °C, an aqueous solution has an equilibrium concentration of 0.00253 M for a generic cation, A2+(aq), and 0.00506 M for a g
aleksandrvk [35]

Answer:

The equilibrium constant Ksp of the generic salt AB2 =  6.4777 *10^-8 M

Explanation:

Step 1: The balanced equation

AB2 ⇒ A2+ + 2B-

Step 2: Given data

Concentration of A2+ = 0.00253 M

Concentration of B- = 0.00506 M

Step 3: Calculate the equilibrium constant

Equilibrium constant Ksp of [AB2] = [A2+][B-]²

Ksp = 0.00253 * 0.00506² = 6.4777 *10^-8 M

The equilibrium constant Ksp of the generic salt AB2 =  6.4777 *10^-8 M

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4 years ago
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Rutherford - B

Bohr - A

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6 0
3 years ago
If an object loses electrons it will become negatively charged. <br><br><br> True<br><br> False
Ray Of Light [21]
The answer should be true.
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Mass of moist aggregate sample as brought to the laboratory: 5,306 grams Mass of oven dried aggregate: 5,229 grams Mass of aggre
Lerok [7]

Answer:

a.   2.748

b. 68.91

c. 1.45%

d. 37.84%

Explanation:

To determine the:

a. The aggregate's bulk Saturated Surface Dry specific gravity

Given:

The mass of the moist aggregate sample is 5,229 g.

The mass of the oven-dried aggregate is 5,306 g.

The mass of the aggregate submerged in water is 5,229 g.

The mass of the Saturated Surface Dry aggregate is 3,298 g.

The aggregate's bulk SSD specific gravity =the dry weight ÷ ( the SSD weight - the submerged weight)

Given:

The mass of the oven-dried aggregate is 5,306 g.

The mass of the Saturated Surface Dry aggregate is 3,298 g.

The mass of the aggregate submerged in water is 5,229 g.

= 5,306 ÷ ( 3,298 - 5,229)

= 5,306 ÷ 1,931 = 2.748

b. The aggregate appearance specific gravity

the aggregate apparent specific gravity = the dry weight ÷ (the dry weight - the submerged weight)

Given:

The mass of the oven-dried aggregate is 5,306 g.

The mass of the aggregate submerged in water is 5,229 g

The aggregate apparent specific gravity = 5,306  ÷ (5,306 - 5,229)

The aggregate apparent specific gravity = 68.91

c. The moist content of stockpile aggregate

The moisture content of stockpile aggregate = ( the moist aggregate weight - the dry weight) ÷ the dry weight

Given:

The mass of the moist aggregate sample is 5,229 g.

The mass of the oven-dried aggregate is 5,306 g

The moisture content of stockpile aggregate = (5,229 - 5,306)  ÷ 5,306

The moisture content of stockpile aggregate = 0.0147 x 100% (when expressed in percentage) = 1.45%

d. Absorption

Absorption =  (mass of the Saturated Surface Dry aggregate - mass of the oven-dried aggregate)  ÷ mass of the oven-dried aggregate x 100%

Given:

The mass of the Saturated Surface Dry aggregate is 3,298 g

The mass of the oven-dried aggregate is 5,306 g.

Absorption =  (3,298  - 5,306)  ÷ 5,306  x 100% = 37.84%

8 0
3 years ago
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