A. <em>Concentration in terms of molarity</em>
First, calculate for the molar mass of the given solution, C12H22O11.
m = 12(12) + 22(1) + 11(16) = 232
Calculate for the number of moles.
n = 8.45 g / 232 g/mol = 0.036422 moles
Divide the determined number of moles by volume of solution in L.
V(solution) = (250 mL)(1 L/1000 mL) = 0.25 L
The concentration in molarity is determined by dividing the number of moles by the volume of solution in liters.
M = 0.03622 moles / 0.25 L = 0.146 moles/L
b. <em>Concentration in terms of molality</em>
Calculate the mass of the solvent in kilogram given the volume and its density.
m(solvent) = (1.21 g/cm3)(250 mL)(1 kg/1000 g) = 0.3025 kg
Divide the calculated number of moles by the mass of the solvent in kilograms.
molality = 0.036422 moles/0.3025 kg = 0.12 molal
c. <em>Concentration in terms of weight percent.</em>
The total weight of the solution is equal to 302.5 g.
weight percent of solute = (8.45 g / 302.5 g)(100%) = 2.79%
d. <em>Weight percent in ppm.</em>
weight percent of solute x (10000 ppm/1%)
= (2.79%)(10000 ppm/1%) = 27933.88 ppm
Hey there!
Mass = 5.6 Kg
Volume =8.2 L
D = m / V
D = 5.6 / 8.2
D = 0.6829 Kg/L
hope this helps!
Answer:
Option a, 
Explanation:
According to Arrhenius concept of acids and bases, acids are those substances which releases H+ in aqueous solution and bases are those which releases OH- in aqueous solution.
Among the given only can release 
in aqueous solution.
LiOH releases 
, therefore it is an Arrhenius base.
and 
cannot releases .
So, the correct option is option a.
Answer:b. Acetoacetate concentration increases.
Explanation:
Answer:
carbon
Explanation:
Atomic radius represents the distance from the nucleus to the outer shell of an element.
