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Leviafan [203]
2 years ago
7

Which of the following will neutralize an acid?

Chemistry
1 answer:
pochemuha2 years ago
8 0
LiOH is going to neutralize the acid because it’s a base
You might be interested in
1)
zaharov [31]

Answer:

B. what happens when iron rusts in the presence of water

Explanation:

Chemistry is a branch of science involving the composition and changes of matter. In other words, a chemist, who is a trained specialist in the science of chemistry, seeks to answer questions related to properties of matter.

In this question, a chemist is most likely to study "what happens when iron rusts in the presence of water" because it involves a change in the chemical properties of a substance (iron) i.e. a chemical change. However, what happens when ice melts to liquid water is a physical change.

3 0
3 years ago
Iron has a density of 7.9 space straight g divided by cm cubed. How much mass is in a 10 space cm cubed sample of iron? Question
dezoksy [38]

Answer:

79 g

Explanation:

Density (d) of iron = 7.9 g/cm³

Volume of the iron (V) = 10 cm³

Mass of the iron (m) = ?

Solution:

Formula will be used

                            d = m/V

As we have to find mass so rearrange the above equation

                              m = dV . . . . . . . . . . . (1)

Put values in above equation 1

                         m = 7.9 g/cm³ x 10cm³

                         m = 79 g

So,

mass of iron = 79 g

6 0
3 years ago
the spectral lines observed for hydrogen arise from transitions from excited states back to the n=2 principle quantum level. Cal
Sunny_sXe [5.5K]

Rydberg formula is given by:

\frac{1}{\lambda } = R_{H}\times (\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} )

where, R_{H} = Rydberg  constant = 1.0973731568508 \times 10^{7} per metre

\lambda = wavelength

n_{1} and n_{2} are the level of transitions.

Now, for n_{1}= 2 and n_{2}= 6

\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{6^{2}} )

= 1.0973731568508 \times 10^{7} \times (\frac{1}{4}-\frac{1}{36} )

= 1.0973731568508 \times 10^{7} \times (0.25-0.0278 )

= 1.0973731568508 \times 10^{7} \times 0.23

= 0.2523958\times 10^{7}

\lambda = \frac{1}{0.2523958\times 10^{7}}

= 3.9620\times 10^{-7} m

= 396.20\times 10^{-9} m

= 396.20 nm

Now, for n_{1}= 2 and n_{2}= 5

\frac{1}{\lambda} = 1.0973731568508 \times  10^{7} \times (\frac{1}{2^{2}}-\frac{1}{5^{2}} )

= 1.0973731568508 \times 10^{7} \times (0.25-0.04 )

= 1.0973731568508 \times 10^{7} \times (0.21 )

= 0.230 \times  10^{7}

\lambda= \frac{1}{0.230 \times 10^{7}}

= 4.3478 \times 10^{-7} m

= 434.78\times 10^{-9} m

= 434.78 nm

Now, for n_{1}= 2 and n_{2}= 4

\frac{1}{\lambda} = 1.0973731568508 \times  10^{7} \times (\frac{1}{2^{2}}-\frac{1}{4^{2}} )

=  1.0973731568508 \times 10^{7} \times (0.25-0.0625 )

= 1.0973731568508 \times 10^{7} \times (0.1875 )

= 0.20575 \times 10^{7}

\lambda= \frac{1}{0.20575 \times 10^{7}}

= 4.8602 \times 10^{-7} m

= 486.02 \times 10^{-9} m

= 486.02 nm

Now, for n_{1}= 2 and n_{2}= 3

\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{3^{2}} )

=  1.0973731568508 \times 10^{7} \times (0.25-0.12 )

=  1.0973731568508 \times 10^{7} \times (0.13 )

= 0.1426585\times 10^{7}

\lambda= \frac{1}{0.1426585\times 10^{7}}

= 7.0097 \times 10^{-7} m

= 700.97 \times 10^{-9} m

= 700.97 nm



5 0
2 years ago
Read 2 more answers
True or False: Mutually beneficial relationships, predator-prey relationships, and competition can happen in different environme
Masja [62]

Answer:

Yes :)

Explanation:

Mutual relationships can include birds cleaning out aligators' teeth, which helps with their hygiene, and gives the bird a meal!

Predator-prey would be a cheetah-antelope.

Competition could be an invasive species :)

8 0
2 years ago
HELP I DON'T HAVE MUCH TIME PLZ HELP ME IF YOU ARE REALLY GOOD AT SCIENCE COME TO MY QUESTION PLEASEEEE Which fossil fuel create
Bas_tet [7]
Hey there!
The correct answer is C

Hope this helps you!

Always remember, you are a Work Of Art!
- Nicole :) <3
6 0
3 years ago
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