3 years ago

How many repeat units are required to make a nylon polymer with a formula weight of 15,000 amu?

1 answer:

5 0

This problem is giving information about a nylon polymer whose molar mass is 15,000 amu (atomic mass units).

The first subject of matter here, is to recall the monomeric molecular formula of nylon which is C₁₂H₂₂N₂O₂, and the definition of monomer (basic molecule able to react and form a polymer) and polymer (assembling of monomers).

Next, we calculate the molar mass of the monomer of nylon:

$12*12.01+22*1.01+2*14.01+2*16.00=226.31amu$

Finally, the number of units is calculated by dividing the molar mass of the polymer and the monomers:

$n=\frac{15000}{226.31} =66.2$

Which is about 66 monomers.

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What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 23 ∘C , V1= 1.69×103 L ) to a v

andrezito [222]

Answer:

319.15^{o}C[/tex]

Explanation:

When all other variables are constant, we are allowed to use the formula

$\frac{T_{2} }{V_{2} } = \frac{T_{1} }{V_{1} } \\Which can be rewritten as T_{2} = \frac{T_{1} V_{2} }{V_{1} }if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to KelvinNow to calculate T2[tex]T_{2}= \frac{296.15K*3.38.10^{3}L }{1.69.10^{3}L }= 592.3K$ = $319.15^{o} C$