How many repeat units are required to make a nylon polymer with a formula weight of 15,000 amu?
1 answer:
This problem is giving information about a nylon polymer whose molar mass is 15,000 amu (atomic mass units).
The first subject of matter here, is to recall the monomeric molecular formula of nylon which is C₁₂H₂₂N₂O₂, and the definition of monomer (basic molecule able to react and form a polymer) and polymer (assembling of monomers).
Next, we calculate the molar mass of the monomer of nylon:
Finally, the number of units is calculated by dividing the molar mass of the polymer and the monomers:
Which is about 66 monomers.
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= 24.3
The average atomic mass of X is the <em>weighted average</em> of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its <em>relative importance</em> (i.e., its % abundance).
Thus,
0.790 × 24 u = 18.96 u
0.100 × 25 u = 2.50 u
0.110 × 26 u = <u>2.86 u</u>
TOTAL = 24.3 u
∴ The relative atomic mass of X is 24.3.