Solid. Because molecules densely packed it has a high resistance to flow thereby lower kinetic energy.
Answer:
1083.6 g
Explanation:
At STP, 1 mol of any given mass will occupy 22.4 L.
With the information above in mind we can<u> calculate how many moles of nitrogen gas (N₂) are there in 867 L</u>:
- 867 L ÷ 22.4 L/mol = 38.7 mol
Finally we convert 38.7 moles of N₂ into grams, using its molar mass:
- 38.7 mol * 28 g/mol = 1083.6 g
Answer:
1.552 moles
Explanation:
First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.
This is illustrated below:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:
Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol
Mass of C8H18 = 22.1g
Mole of C8H18 =..?
Number of mole = Mass /Molar Mass
Mole of C8H18 = 22.1/144
Mole of C8H18 = 0.194 mole
From the balanced equation above,
2 moles of C8H18 produced 16 moles of CO2.
Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.
Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned
Answer:
NBr3 has a trigonal pyramidal geometry where the nitrogen atom is bonded to three bromine atoms and has one lone pairs. The individual bonds are polar, as bromine is less electronegative than nitrogen. The overall compound is also polar, as the dipoles do not cancel.
Explanation:
Answer:
Would be increasing the concentration of SO3 as you chose in the question.
Explanation:
Increasing the concentration of the reactant will most likely shift it to the right by adding more products.