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3 years ago

In comparing 1 mole of carbon atoms to one mole of magnesium atoms, which statement is TRUE?

Chemistry

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

Explanation:

A) The molecular mass of a compound is the atomic mass of this compound but in grams, we know that the magnesium has an atomic mass of 24 u and the carbon has and atomic mass of 12 u, so the molecular mass of magnesium is 24g and the molecular mass of carbon is 12g, so a mole of magnesium has a greater mass.

B) A mole of any given substance is the avogadro number, 6.023 10^23 molecules, so a mole of magnesium and a mole of carbon has the same amount of atoms.

C) The molecular mass of a compound is the atomic mass of this compound but in grams, we know that the magnesium has an atomic mass of 24 u and the carbon has and atomic mass of 12 u, so the molecular mass of magnesium is 24g and the molecular mass of carbon is 12g, so a mole of magnesium has a greater mass.

D) The molecular mass of a compound is the atomic mass of this compound but in grams, we know that the magnesium has an atomic mass of 24 u and the carbon has and atomic mass of 12 u, so the molecular mass of magnesium is 24g and the molecular mass of carbon is 12g, so a mole of magnesium has a greater mass.

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Select all of the following statements that represent the differences between a voltaic cell and an electrolytic cell. Group of

Sunny_sXe [5.5K]

Answer:

The electrodes will change in mass for only the electrolytic cell

Electrode with the lowest reduction potential is reduced in an electrolytic cell

A potential is generated when the voltaic cell runs

6 0

3 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

3 years ago

Read 2 more answers

A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s

Lilit [14]

Answer:

pH = 1.32

Explanation:

H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M

54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

3 0

3 years ago

7. Suppose each of these isotopes emits a beta particle. Give the iso-

Volgvan

In a beta emission, the mass number of the daughter nucleus remains unchanged while the atomic number of the daughter nucleus increases by one unit. The following are isotopes produced when the following undergo beta emission;

1) potassium-42 ------> Ca - 42

2) iodine-131 ------------> Xe - 131

3) iron-52 ---------------> Co - 52

4) sodium-24 -----------> Mg -24

The daughter nucleus formed after beta emission is found one place after its parent in the periodic table.

Regarding the stability of the daughter nuclei, a nucleus is unstable if the neutron-proton ratio is less than 1 or greater than 1.5.

Hence, the following daughter nuclei are stable; Ca - 42, Xe - 131, Mg -24.

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3 years ago

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Answer:

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