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3 years ago

In comparing 1 mole of carbon atoms to one mole of magnesium atoms, which statement is TRUE?

Chemistry

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

Explanation:

A) The molecular mass of a compound is the atomic mass of this compound but in grams, we know that the magnesium has an atomic mass of 24 u and the carbon has and atomic mass of 12 u, so the molecular mass of magnesium is 24g and the molecular mass of carbon is 12g, so a mole of magnesium has a greater mass.

B) A mole of any given substance is the avogadro number, 6.023 10^23 molecules, so a mole of magnesium and a mole of carbon has the same amount of atoms.

C) The molecular mass of a compound is the atomic mass of this compound but in grams, we know that the magnesium has an atomic mass of 24 u and the carbon has and atomic mass of 12 u, so the molecular mass of magnesium is 24g and the molecular mass of carbon is 12g, so a mole of magnesium has a greater mass.

D) The molecular mass of a compound is the atomic mass of this compound but in grams, we know that the magnesium has an atomic mass of 24 u and the carbon has and atomic mass of 12 u, so the molecular mass of magnesium is 24g and the molecular mass of carbon is 12g, so a mole of magnesium has a greater mass.

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Which Two of the following are pure substances*

Snowcat [4.5K]

Answer:

I think A and B

Explanation:

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3 years ago

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What material is the source for commercial production of each of the following elements:(a) aluminum;

AleksandrR [38]

The material which is used as source for commercial production aluminum is bauxite.

The aluminum can be extracted from bauxite ore by the process of Bayer process.

In the Bayer process, bauxite ore is heated in the pressure vessel along with a caustic soda solution (sodium hydroxide) at a temperature between 150 to 200 °C. At this temperatures, the aluminium is dissolved in the solution as sodium aluminate in the extraction process. After separation of the residue by filtering, when the liquid is cooled gibbsite is precipitated and then it is seeded with fine-grained aluminum hydroxide crystals from previous extractions. The precipitation take 7-19 days without the addition of seed crystals.

This extraction process converts the aluminium oxide to soluble sodium aluminate, NaAlO2, which afterward converted into aluminum hydroxide and then into aluminum oxide.

Thus, we concluded that the material which is used as source for commercial production aluminum is bauxite ore.

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2 years ago

Calculate the solubility of o2 in water at a partial pressure of o2 of 120 torr at 25 ̊c. the henry's law constant for o2 at 25

Vladimir79 [104]

Answer:

1) 2.054 x 10⁻⁴ mol/L.

2) Decreasing the temperature will increase the solubilty of O₂ gas in water.

Explanation:

1) The solubility of O₂ gas in water:

We cam calculate the solubility of O₂ in water using Henry's law: <em>Cgas = K P</em>,

where, Cgas is the solubility if gas,

K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),

P is the partial pressure of O₂ (P = 120 torr / 760 = 0.158 atm).

Cgas = K P = (1.3 x 10⁻³ mol/l atm) (0.158 atm) = 2.054 x 10⁻⁴ mol/L.

2) The effect of decreasing temperature on the solubility O₂ gas in water:

Decreasing the temperature will increase the solubilty of O₂ gas in water.

When the temperature increases, the solubility of O₂ gas in water will decrease because the increase in T will increase the kinetic energy of gas particles and increase its motion that will break intermolecular bonds and escape from solution.

Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.

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3 years ago

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Which is an example of pure chemistry? a. shape of a soybean plant b. chemicals containing carbon c. finding an antidote

Rina8888 [55]

I believe that it is B chemicals containing carbon

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How many grams of sodium nitrate. NaNO3, are soluble in 100

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Answer:

Your correct answer is D. 40 g