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Nat2105 [25]
2 years ago
12

A student has a large number of coins of different diameters, all made by the same metal. She wishes to find the density of the

metal by a method of placing the coins in the water.
a. Describe how the measurements of the required quantities are carried out.
b. State ONE precaution taken when carrying out the measurements in A to ensure that the results are accurate as possible.
Chemistry
1 answer:
Elenna [48]2 years ago
6 0

Answer:

A. In a graduated cylinder, put some quantity of water and measure the initial volume. Then put a coin and measure the volume. To find the volume of the coin, simply subtract the initial volume (water only) from the ending volume (water + coin). To measure the mass, take a dry coin and place it on an electronic scale. Density = mass / volume, so divide the mass by the volume to calculate the density of the coin.

B. When measuring the volume, make sure to look at the graduated cylinder at eye level and read from the bottom of the meniscus.

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What is the element that is in period 5 and group 3?
rjkz [21]

Answer:

Rubidium

Rubidium is the first element placed in period 5. 

6 0
3 years ago
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
A solution is prepared by dissolving 106.3 g HCl(g) in enough water to make 175.0 L of solution. The ph of this solution is
DedPeter [7]

Answer:

moles HCl = 101.2 g /36.461 g/mol=2.78

[H+]= 2.78 mol/ 150 L =0.0185

pH = - log 0.0185=1.73

1.73 is the answer

3 0
3 years ago
Which of the metals below will dissolve in hydrochloric acid, HCl? gold, Au copper, Cu silver, Ag magnesium, Mg
Lera25 [3.4K]
Magnesium (Mg)

The reason for this is the reactivity of the listed metals. Gold and silver are extremely unreactive metals. It is because of this unreactive nature that they remain in good condition for long periods of time, and are preferred in jewelry. Copper, although more reactive than gold and silver, is still not reactive enough to react with HCl. 
The only metal that will react is magnesium.
7 0
3 years ago
If you have a truckload of icecream, a bucket of sauce, a box of peanuts but only 1 cherry, you can only make 1 complete sundae.
MAXImum [283]

Answer:

<em>Only 5 sundaes can be made</em>

<em>The limiting reagent is the peanuts.</em>

Explanation:

The complete question is

A perfect ice cream sundae requires exactly:

• 3 scoops of ice cream

• 2 squirts of chocolate sauce

• 1 spoon of peanuts

• 1 cherry

If you have 7 scoops of ice cream, 3 spoons of peanuts, 5 cherries and 11 squirts of sauce, you can only

make 2 complete sundaes. In this case, the icecream is the limiting reagent.

If you have a truckload of icecream, a bucket of sauce, a box of peanuts but only 1 cherry, you can only  make 1 complete sundae. In this case the cherry is the limiting reagent.  The limiting reagent is the term given to the ingredient (read: reactant) that has the (stoichiometrically) least  amount. The other reactants are said to be in excess. In a reaction the limiting reagent will be totally  consumed, and some of the reactant in excess will be leftover.

Critical thinking questions

1. If you have 20 scoops of ice cream, 14 squirts of chocolate sauce, 5 spoons of peanuts and 7 cherries,

how many sundaes can you make and which ingredient is the limiting reagent?

From the ingredients for a a complete sundae given above,

20 scoops of icecream will make 20/3 = 6.66 sundaes

14 squirts of chocolate sauce will make 14/2 = 7 sundaes

5 spoonful of peanuts will make 5/1 = 5 sundaes

7 cherries will make 7/1 = 7 sundaes

From the above, we can work out that only 5 sundaes can be made, and the limiting agent here is peanuts, which has the least amount of sundae that can be made from its available amount.

5 0
3 years ago
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