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Nat2105 [25]
2 years ago
12

A student has a large number of coins of different diameters, all made by the same metal. She wishes to find the density of the

metal by a method of placing the coins in the water.
a. Describe how the measurements of the required quantities are carried out.
b. State ONE precaution taken when carrying out the measurements in A to ensure that the results are accurate as possible.
Chemistry
1 answer:
Elenna [48]2 years ago
6 0

Answer:

A. In a graduated cylinder, put some quantity of water and measure the initial volume. Then put a coin and measure the volume. To find the volume of the coin, simply subtract the initial volume (water only) from the ending volume (water + coin). To measure the mass, take a dry coin and place it on an electronic scale. Density = mass / volume, so divide the mass by the volume to calculate the density of the coin.

B. When measuring the volume, make sure to look at the graduated cylinder at eye level and read from the bottom of the meniscus.

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Which statement describes both homogeneous mixtures and heterogeneous mixtures?
stiks02 [169]

Answer:

both are the types of mixture and both are impure substances that donot have fixed composition and the composition of constituents  is not uniform

5 0
3 years ago
The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = {1mg /mL}{\text{Molar mass of myoglobin}}

c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L

1 mg = 0.001 g, 1 mL = 0.001 L

A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0
4 years ago
What volume of propane (C3H8) is required to produce 165 liters of water according to the following reaction? (All gases are at
inna [77]

Answer:

We need 41.2 L of propane

Explanation:

Step 1: Data given

volume of H2O = 165 L

Step 2:  The balanced equation

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Step 3: Calculate moles of H2O

1 mol = 22.4 L

165 L = 7.37 moles

Step 4: Calculate moles of propane

For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O

For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane

Step 5: Calculate volume of propane

1 mol = 22.4 L

1.84 moles = 41.2 L

We need 41.2 L of propane

6 0
4 years ago
How many moles are in 75.0 grams of nitrogen gas, N2?
Westkost [7]

<u>Given:</u><u>                                                                                                                       </u>

Mass of Nitrogen (N₂) gas = 75 grams

<u>Finding the number of moles of N₂:</u><u>                                                                     </u>

We know that the molar mass of N₂ is 28 grams/mole

Number of moles = Given mass / Molar mass

Number of moles = 75 / 28

Number of moles = 2.68 moles

Hence, there are 2.68 moles in 75 grams of Nitrogen Gas

7 0
3 years ago
When a solute is dissolved in water, it forms……
il63 [147K]

Answer:

an aqueous species is the answer

3 0
3 years ago
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