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maw [93]
3 years ago
10

How many mol of sodium hydroxide are required to make 1.35 L of 2.50 mL solution?

Chemistry
1 answer:
Nata [24]3 years ago
6 0
3 and a half mL because
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Which of the following is a precipitation reaction?
fredd [130]

Answer:

B is a precipitation reaction.

Explanation:

This is because a precipitation reaction is when a solid is made from the combination of cations and anions in a solution to create a solid.

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What product(s) are formed during the complete combustion reaction that occurs when methane (CH4) and molecular oxygen (O2) reac
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Explanation: I already took the test it's right

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Two solutions namely, 500 ml of 0.50 m hcl and 500 ml of 0.50 m naoh at the same temperature of 21.6 are mixed in a constant-pre
weeeeeb [17]

24.6 ℃

<h3>Explanation</h3>

Hydrochloric acid and sodium hydroxide reacts by the following equation:

\text{HCl} \; (aq) + \text{NaOH} \; (aq) \to \text{NaCl} \; (aq) + \text{H}_2\text{O} \; (aq)

which is equivalent to

\text{H}^{+} \; (aq) + \text{OH}^{-} \; (aq) \to \text{H}_2\text{O}\; (l)

The question states that the second equation has an enthalpy, or "heat", of neutralization of -56.2 \; \text{kJ}. Thus the combination of every mole of hydrogen ions and hydroxide ions in solution would produce 56.2 \; \text{kJ} or 56.2 \times 10^{3}\; \text{J} of energy.

500 milliliter of a 0.50 mol per liter "M" solution contains 0.25 moles of the solute. There are thus 0.25 moles of hydrogen ions and hydroxide ions in the two 0.500 milliliter solutions, respectively. They would combine to release 0.25 \times 56.2 \times 10^{3} = 1.405 \times 10^{4} \; \text{J} of energy.

Both the solution and the calorimeter absorb energy released in this neutralization reaction. Their temperature change is dependent on the heat capacity <em>C</em> of the two objects, combined.

The question has given the heat capacity of the calorimeter directly.

The heat capacity (the one without mass in the unit) of water is to be calculated from its mass and <em>specific</em> heat.

The calorimeter contains 1.00 liters or 1.00 \times 10^{3} \; \text{ml} of the 1.0 gram per milliliter solution. Accordingly, it would have a mass of 1.00 \times 10^{3} \; \text{g}.

The solution has a specific heat of 4.184 \; \text{J} \cdot \text{g}^{-1} \cdot \text{K}^{-1}. The solution thus have a heat capacity of 4.184 \times 1.00 \times 10^{3} = 4.184 \times 10^{3} \; \text{J} \cdot\text{K}^{-1}. Note that one degree Kelvins K is equivalent to one degree celsius ℃ in temperature change measurements.

The calorimeter-solution system thus has a heat capacity of 4.634 \times 10^{3} \; \text{J} \cdot \text{K}^{-1}, meaning that its temperature would rise by 1 degree celsius on the absorption of 4.634 × 10³ joules of energy. 1.405 \times 10^{4} \; \text{J} are available from the reaction. Thus, the temperature of the system shall have risen by 3.03 degrees celsius to 24.6 degrees celsius by the end of the reaction.

4 0
3 years ago
Classify the following as a solution, suspension or colloid
frosja888 [35]

Answer:

Solution - (a) Brine . Suspension - (c) sand and water, (g) chalk and water​ Colloid - (e) air,  (f) smoke , (d) soda , (b) milk

Explanation:

A solution is an homogeneous mixture of two or more compounds.

A suspension is a heterogeneous mixture of two or more compounds while a colloid is a homogeneous mixture of two or more compounds with suspended particles which do not settle.

So, under these definitions, the classifications are as follows-

Solution - (a) Brine .

Suspension - (c) sand and water, (g) chalk and water​

Colloid - (e) air,  (f) smoke , (d) soda , (b) milk

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The day's length is not a settled unit of time.

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The day's length changes amid the time and in addition about predictably or something to that effect, and extra hop second is added to the timetable.
The second is portrayed using different unrests of the cesium 133 particle at 0 Kelvin in light of the fact that isolated from quantum mechanics, it isn't at risk to coincidental segments.


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