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3 years ago

Simplify 8^-7 x 8^5 please show work

Mathematics

1 answer:

Pie3 years ago

7 0

When you are multiplying exponents with the same base, you can add the exponents. This is represented as:

$x^a \cdot x^b = x^{(a +b)}$

In our case we are multiplying exponents with the same base 8 and exponents -7 and 5. The sum of -7 and 5 is -2, so our answer is $\boxed{8^{-2}}$ .

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Y= 1/2x+ 2 to make the x the subject.

timofeeve [1]

Answer:

$x=2y-4$

Step-by-step explanation:

$y=\frac{1}{2} x+2$

"To make x the subject" means to have the equation with all the terms in x on one side. As of now, y is the subject of the equation.

You start by subtracting 2 from both sides, you should get the following.

$y-2=\frac{1}{2} x$

Then you multiply by 2 from both sides, you should end up with the following.

$2(y-2)=x$

Therefore, you get the following.

$x=2(y-2)$

Finally, you distribute and get the answer.

$x=2y-4$

5 0

2 years ago

Find the first six terms of the sequence. a1 = 1, an = 4 • an-1

maksim [4K]

$\bf \begin{array}{ccllll}
n&term&value\\
---&-----&-----\\
1&a_1&1\\
2&a_2&4\cdot a_{2-1}\\
&&4\cdot a_1\\
&&4\\
3&a_3&4\cdot a_{3-1}\\
&&4\cdot a_2\\
&&16\\
4&a_4&4\cdot a_{4-1}\\
&&4\cdot a_3\\
&&64\\
5&a_5&4\cdot a_{5-1}\\
&&4\cdot a_4\\
&&256\\
6&a_6&4\cdot a_{6-1}\\
&&4\cdot a_5\\
&&1024
\end{array}$

3 0

3 years ago

WILL GIVE BRAINLIEST

jasenka [17]

$45,600

12 (200 + 75s)
12 ((200 + 75 (48))
12 ( 200 + 3600)
12 (3800)
45600

8 0

3 years ago

Read 2 more answers

A fraternity charged $2.00 admission for dudes and $1.00 admission for ladies to their finals week bash. The fraternity made $75

lisabon 2012 [21]

<span>20 tickets for guys @ $2 = $40
35 tickets for gals @ $1 = $35
Total = 55 tickets and $75</span>

3 0

3 years ago

Find the value of sin(a/2) if cosa= 12/13<br>

daser333 [38]

Answer: sin $\frac{a}{2}$ = ± $\frac{1}{\sqrt{26} }$

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ± $\sqrt{(1-} \frac{cos2A}{2} )$

As required, set A = $\frac{a}{2}$ & cos a= $\frac{12}{13}$ ,thus we get

sin $\frac{a}{2}$ =± $\sqrt{\frac{1-cos a}{2} }$

∴ sin $\frac{a}{2}$ =± $\sqrt{\frac{1-\frac{12}{13} }{2} }$ = ± $\frac{1}{\sqrt{26} }$

since ,360° < $\frac{a}{2}$ <450°

,180° < $\frac{a}{2}$ <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

5 0

3 years ago