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Zolol [24]
3 years ago
5

Simplify 8^-7 x 8^5 please show work

Mathematics
1 answer:
Pie3 years ago
7 0

When you are multiplying exponents with the same base, you can add the exponents. This is represented as:

x^a \cdot x^b = x^{(a +b)}


In our case we are multiplying exponents with the same base 8 and exponents -7 and 5. The sum of -7 and 5 is -2, so our answer is \boxed{8^{-2}}.

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Y= 1/2x+ 2 to make the x the subject.
timofeeve [1]

Answer:

x=2y-4

Step-by-step explanation:

y=\frac{1}{2} x+2

"To make x the subject" means to have the equation with all the terms in x on one side. As of now, y is the subject of the equation.

You start by subtracting 2 from both sides, you should get the following.

y-2=\frac{1}{2} x

Then you multiply by 2 from both sides, you should end up with the following.

2(y-2)=x

Therefore, you get the following.

x=2(y-2)

Finally, you distribute and get the answer.

x=2y-4

5 0
2 years ago
Find the first six terms of the sequence. a1 = 1, an = 4 • an-1
maksim [4K]
\bf \begin{array}{ccllll}
n&term&value\\
---&-----&-----\\
1&a_1&1\\
2&a_2&4\cdot a_{2-1}\\
&&4\cdot a_1\\
&&4\\
3&a_3&4\cdot a_{3-1}\\
&&4\cdot a_2\\
&&16\\
4&a_4&4\cdot a_{4-1}\\
&&4\cdot a_3\\
&&64\\
5&a_5&4\cdot a_{5-1}\\
&&4\cdot a_4\\
&&256\\
6&a_6&4\cdot a_{6-1}\\
&&4\cdot a_5\\
&&1024
\end{array}
3 0
3 years ago
WILL GIVE BRAINLIEST
jasenka [17]
$45,600

12 (200 + 75s)
12 ((200 + 75 (48))
12 ( 200 + 3600)
12 (3800)
45600
8 0
3 years ago
Read 2 more answers
A fraternity charged $2.00 admission for dudes and $1.00 admission for ladies to their finals week bash. The fraternity made $75
lisabon 2012 [21]
<span>20 tickets for guys @ $2 = $40
35 tickets for gals @ $1 = $35
Total = 55 tickets and $75</span>
3 0
3 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
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