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horsena [70]
4 years ago
11

If you applied a 11 N force to a box and made it travel 108 m in 7

Physics
1 answer:
snow_lady [41]4 years ago
6 0

Explanation:

due to the local people in the advantage and the value of that house so that there were no people this answer was belonging to define in refinery of the circuit

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In higher mass stars, repeating cycles of fusion will create heavier elements in layers
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The element is iron.
4 0
3 years ago
The free body diagram four objects are shown Which object has a net force of -5 N down?​
max2010maxim [7]

Answer:

F-5-89

Explanation:

7 0
3 years ago
If it took 3 hours to clean 6 houses, how many houses could be cleaned in 12 hours?
mel-nik [20]

Answer:

24

Explanation:

If it took 3 hours to clean 6 houses than you can figure that is 2 houses per hours. so if there are 12 hours and 2 houses an hour, you multiply 12x2 and get 24. Another way to do it is to use proportions (aka two fractions that equal eachother):

  3 hours                12 hours

----------------    =    ---------------

 6 houses          number of houses

To calculate this, we can think about how we go from 3 to 12. Well, 3x4 is 12, so we got to 12 by doing multiplying by 4. So we can multiply 6 by 4 and you get 24.

<u><em>Hope it helps! have a great day :)</em></u>

8 0
3 years ago
Read 2 more answers
Hey, what is antimatter
jenyasd209 [6]
A antimatter is particle physics, antimatter is a material composed of the antiparticle "partners" to the corresponding particles of ordinary matter. A particle and its antiparticle have the same mass as one another, but opposite electric charge and other quantum numbers.
5 0
3 years ago
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Consider two planets in space that gravitationally attract each other if the mass of one of them stays the same and the mass of
irga5000 [103]

Answer:

D. half as much

Explanation:

let m and M be the mass of the planets and r be the distance between them.

then: the force of attraction between them is given by,

F = G×m×M/(r^2)

if we keep one mass constant and double the other and also double the distance between them.

the force of attraction becomes:

F1 = 2G×m×M/[(2×r)^2]

   = 2G×m×M/[4×(r)^2]

   = (1/2)G×m×M/(r^2)

   = 1/2×F

therefore, when you double one mass and keep the other mass constant and double the distance between the masses you decrease the force by a factor of 1/2.

8 0
3 years ago
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