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schepotkina [342]
3 years ago
8

A capoeira é muito mais que uma luta, por isso os campeonatos internos tem o objetivo de: 1 ponto Testar a força dos participant

es. Criar lutadores profissionais. Avaliar o indivíduo como um todo. Competir quem faz mais golpes.
Physics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

Avaliar o indivíduo como um todo.

Explanation:

O graduado na capoeira, é uma pessoa que recebe mais respeito pelo grupo. Sendo portanto o objetivo de cada exame interno, ou pelo menos deveria ser em sua vasta maioria avaliar o indivíduo como um todo.

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A system of ideal gas at 22°C undergoes an ischoric process with an internal energy decrease of 4.30 × 10 3 4.30×103 J to a fina
Komok [63]

Answer:

The approximate change in entropy is -14.72 J/K.

Explanation:

Given that,

Temperature = 22°C

Internal energy U=4.30\times10^{3}\ J

Final temperature = 16°C

We need to calculate the approximate change in entropy

Using formula of the entropy

\Delta S=\dfrac{\Delta U}{T}

Where, \Delta U = internal energy

T = average temperature

Put the value in to the formula

\Delta S=\dfrac{-4.30\times10^{3}}{\dfrac{22+273+16+273}{2}}

\Delta S=-14.72\ J/K

Hence, The approximate change in entropy is -14.72 J/K.

5 0
3 years ago
Given A=125.0=0.4 and 25.0=0.1 calculate A-B<br><br><br><br><br>​
kicyunya [14]

Answer: Find an answer to your question given A=125.0=0.4 and 25.0=0.1 calculate A-B​

Explanation:

6 0
3 years ago
Q.1- Find the distance travelled by a particle moving in a straight line with uniform acceleration, in the 10th unit of time.
Korolek [52]

Answer:

If the acceleration is constant, the movements equations are:

a(t) = A.

for the velocity we can integrate over time:

v(t) = A*t + v0

where v0 is a constant of integration (the initial velocity), for the distance traveled between t = 0 units and t = 10 units, we can solve the integral:

\int\limits^{10}_0 {A*t + v0} \, dt = ((A/2)10^2 + v0*10) = (A*50 + v0*10)

Where to obtain the actual distance you can replace the constant acceleration A and the initial velocity v0.

4 0
3 years ago
What is the weight of an 1000 gram mass
Reil [10]

That depends on where you weigh it.

-- On Earth, it weighs 9.807 newtons (2.205 pounds).

-- On the moon, it weighs 1.623 newtons (5.84 ounces).

-- On Jupiter, it weighs 24.79 newtons (5.57 pounds).

BTW ... 1,000 grams of mass is called ' one kilogram '.





8 0
3 years ago
Read 2 more answers
calculate the acceleration of a 41-kg crate of baseball gear when pulled sideways with a net force of 1255 N. neglect frictional
lara31 [8.8K]

In his celebrated Second Law of Motion, Newton wrote:

             Net force  =  (mass) x (acceleration).

By the process of "plugging in numbers", we can write

             1255 N  =  (41 kg) x (acceleration)

Now, after dividing each side by (41 kg), we have

             (1255 N) / (41 kg)  =  acceleration.

But  (1255N)/(41kg) = 30.61 m/s² .

So unless we have carelessly blooped the calculations somewhere,
that  30.61 m/s²  is the answer we're looking for.
  
7 0
3 years ago
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