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schepotkina [342]
3 years ago
8

A capoeira é muito mais que uma luta, por isso os campeonatos internos tem o objetivo de: 1 ponto Testar a força dos participant

es. Criar lutadores profissionais. Avaliar o indivíduo como um todo. Competir quem faz mais golpes.
Physics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

Avaliar o indivíduo como um todo.

Explanation:

O graduado na capoeira, é uma pessoa que recebe mais respeito pelo grupo. Sendo portanto o objetivo de cada exame interno, ou pelo menos deveria ser em sua vasta maioria avaliar o indivíduo como um todo.

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An old-fashioned LP record rotates at 33 1/3 RPM
Ksenya-84 [330]

Answer:

Part a) \frac{5}{9}\ \frac{rev}{sec}

Part b) \frac{9}{5}\ \frac{sec}{rev}

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

so

33\frac{1}{3}\ \frac{rev}{min}

Convert mixed number to an improper fraction

33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}

Remember that

1\ min=60\ sec

Convert rev/min to rev/sec

\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}

Simplify

\frac{5}{9}\ \frac{rev}{sec}

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

\frac{9}{5}\ \frac{sec}{rev}

4 0
3 years ago
A 5kg rock and a 10kg rock are dropped from a height of 10m?
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Look out below ! You should step nimbly to one side, to avoid being hit by one or the other of those hazardous weight objects when they arrive (at the same time).
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The ____ of an object is a measure of the amount of matter it contains. on the other hand ____ is a measure of the gravitational
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7 0
3 years ago
A go-cart is rolling down a hill at 15m/s. If it has 85J of kinetic energy. what is the mass of the go-cart?
hichkok12 [17]
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3 0
2 years ago
What is the acceleration of the the object during the first 4 seconds?
AVprozaik [17]

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

6 0
3 years ago
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