Question

A very large sheet of a conductor carries a uniform charge density of on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor?

Answer 1

Complete Question

A very large sheet of a conductor carries a uniform charge density of $4.00\ pC/mm^2$  on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor?

Answer:

The electric field is  $E = 4.5198 *10^{5} \ N/C$

Explanation:

From the question we are told that

    The charge density is  $\sigma = 4.00pC /mm^2 = 4.00 * 10^{-12 } * 10^{6} = 4.00 *10^{-6}C/m$

    The position outside the surface is  $a = 3.00 \ mm = 0.003 \ m$

   

Generally the electric field is mathematically represented as

          $E = \frac{\sigma}{\epsilon _o }$

Where  $\epsilon_o$ is  the permitivity of free space with values  $\epsilon _o = 8.85 *10^{-12} F/m$

substituting values  

           $E = \frac{4.0*10^{-6}}{8.85 *10^{-12} }$

           $E = 4.5198 *10^{5} \ N/C$