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Simora [160]
3 years ago
15

The sound level at 1.0 m from a certain talking person talking is 60 dB. You are surrounded by five such people, all 1.0 m from

you and all talking equally loud at the same time. The threshold of hearing is 1.0 × 10-12 W/m2. What sound level are you being exposed to? You can neglect any absorption, reflection, or interference of the sound. The threshold of hearing is 1.0 × 10-12 W/m2.
Physics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

66.98 db

Explanation:

We know that

L_T=L_S+10log(n)

L_T= Total signal level in db

n= number of sources

L_S= signal level from signal source.

L_T=60+10 log(5)

= 66.98 db

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Two rams run toward each other. One ram has a mass of 49 kg and runs west
olga nikolaevna [1]

Answer: (d)

Explanation:

Given

Mass of the first ram m_1=49\ kg

The velocity of this ram is v_1=-7\ m/s

Mass of the second ram m_2=52\ kg

The velocity of this ram v_2=9\ m/s

They combined after the collision

Conserving the momentum

\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]

Momentum after the collision will be

\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}

Therefore, option (d) is correct

4 0
3 years ago
Please help me with this physics prooblem
zaharov [31]

Take the missile's starting position to be the origin. Assuming the angles given are taken to be counterclockwise from the positive horizontal axis, the missile has position vector with components

x=v_0\cos20.0^\circ t+\dfrac12a_xt^2

y=v_0\sin20.0^\circ t+\dfrac12a_yt^2

The missile's final position after 9.20 s has to be a vector whose distance from the origin is 19,500 m and situated 32.0 deg relative the positive horizontal axis. This means the final position should have components

x_{9.20\,\mathrm s}=(19,500\,\mathrm m)\cos32.0^\circ

y_{9.20\,\mathrm s}=(19,500\,\mathrm m)\sin32.0^\circ

So we have enough information to solve for the components of the acceleration vector, a_x and a_y:

x_{9.20\,\mathrm s}=\left(1810\,\dfrac{\mathrm m}{\mathrm s}\right)\cos20.0^\circ(9.20\,\mathrm s)+\dfrac12a_x(9.20\,\mathrm s)^2\implies a_x=21.0\,\dfrac{\mathrm m}{\mathrm s^2}

y_{9.20\,\mathrm s}=\left(1810\,\dfrac{\mathrm m}{\mathrm s}\right)\sin20.0^\circ(9.20\,\mathrm s)+\dfrac12a_y(9.20\,\mathrm s)^2\implies a_y=110\,\dfrac{\mathrm m}{\mathrm s^2}

The acceleration vector then has direction \theta where

\tan\theta=\dfrac{a_y}{a_x}\implies\theta=79.2^\circ

5 0
3 years ago
Choose all of the true statements regarding the relationship between voltage, resistance, and current. Current is measured in am
AveGali [126]

-- <u><em>Current is measured in amps.</em></u>  (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".)

-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>

-- <u><em>Current is the flow of electrons through a circuit.</em></u>

-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.)  <u><em>It should be V = I · R</em></u> .  

(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.)  <u><em>If the resistance is what you're looking for, then the equation to use is  </em></u><u><em>R = V / I</em></u><u><em> .  </em></u>

<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>

6 0
4 years ago
Read 2 more answers
A sophomore with nothing better to do adds heat to a mass 0.300 kg of ice at 0.0 âc until it is all melted.
kramer
Melting ice?  Man, that's cold
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3 years ago
16. Kinematic equations can only be used if...​
Effectus [21]

the acceleration or the next force acting on the body is constant

7 0
3 years ago
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