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Goshia [24]
3 years ago
14

If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th

ere?
Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

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In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
3 years ago
-5+7q+ -5q+ -9q please help
vekshin1

For this case we must simplify the following expression

-5 + 7q + (- 5q) + (- 9q)

We know that, by definition:

+ * - = -

So, rewriting the expression we have:

-5 + 7q-5q-9q =

We add similar terms taking into account that:

  • Equal signs are added and the same sign is placed.
  • Different signs are subtracted and the major's sign is placed:

-5 + 2q-9q =\\-5-7q

Answer:

-5-7q

5 0
4 years ago
Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor
Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

the lengths of the sides of BRAD are:

\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}

The lengths of the sides of KELY are:

\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}

Each side of KELY is twice the length of the corresponding side on BRAD.  This makes the ratio of the sides 2:1 and the figures are similar.

8 0
3 years ago
Read 2 more answers
Please help me thank you. 16 points and show all work.
Solnce55 [7]

magnitude = sqrt(6^2+4^2)

= sqrt ( 36+16)

=sqrt (52) = 7.2


angle = tan^-1(6/4) = 56 degrees


5 0
3 years ago
Abby has x dolls. Lauren has 9 times as many as Abby. Betsy has 7 fewer than Lauren. How many dolls do they have in all?
makkiz [27]

Answer: x + 9x + (9x - 7)

Simplified: 19x - 7

Step-by-step explanation: We see that Abby already starts off with x dolls. We put a 9 infront of the x for the second part of the expression because Lauren has 9 times as many dolls as Abby. Since Betsy has 7 less than Lauren, we take away 7 from 9x. We put that part in parenthesis because that part needs to be done first before we add everything together. Once simplified, we have "19x - 7". (I really tried my best so I hope this is the correct answer!)

5 0
3 years ago
Read 2 more answers
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