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Goshia [24]
3 years ago
14

If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th

ere?
Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

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34 divided 5323 in simple form
joja [24]

The value when 34 is divided by 5323 is 0.00639.

<h3>What is division?</h3>

It should be noted that division simply means the opposite of multiplication. It represents the way numbers are combined in order to make new numbers.

The steps include:

1: Take the dividend's first digit starting from the left in step one. Verify if this digit exceeds or is equal to the divisor.

2. Next, divide it by the divisor, and write the result as the quotient on top.

3. Subtract the outcome from the digit, and then put the difference below.

4: Decrease the dividend's subsequent digit (if present).

5: Carry out Step 4 again.

In this case, 34 divided 5323 will be 0.00639. It should be noted that this illustrates a decimal.

Learn more about division on:

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