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charle [14.2K]
4 years ago
11

Which expression is equivalent to

Mathematics
2 answers:
Naya [18.7K]4 years ago
7 0
C is the correct answer
eimsori [14]4 years ago
4 0

Answer:

C. -\sqrt[3]{x}^5

Step-by-step explanation:

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Sorry I'm not good at math but I just want to learn how to do this
kolezko [41]
The answer is 8.6. I hope this helped you out!
4 0
4 years ago
Gerald wants to buy a sweater that is $41.60 because it is on sale for 20% off
vovangra [49]

Answer: $33.28

Step-by-step explanation: 41.60x .20 = 8.32

41.60 - 8.32 = 33.28

3 0
3 years ago
Use compatible numbers to estimate the quotient of 776÷28
kiruha [24]
The answer to ur division problem would be 27.6785714286<span>
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4 0
3 years ago
A circle has a diameter of 15 meters. Calculate the
Nina [5.8K]

Answer:

15.7 meters

Step-by-step explanation:

Applying,

s = πd∅/360°..................... Equation 1

Where s = length of the arc formed, d = diameter of the circle, ∅ = angle formed by the center of the circle, π = pie.

From the question,

Given: d = 15 meters, ∅ = 120°

Constant: π = 3.14

Substitute these values into equation 1

s = (3.14×15×120)/360

s = 15.7 meters

Hence the lenght of the arc formed is 15.7 meters

4 0
3 years ago
A new car costs $34,000 and its value depreciates at 14% of its value each year. What is the decay factor for the value of this
inessss [21]

The price of the car after 10 years is $7524.25 if the new car costs $34,000 and its value depreciates at 14% of its value each year.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let y represent the value of the car after x years. A new car costs $34,000 and its value depreciates at 14% of its value each year. Hence:

y = 34000(0.86)ˣ

After 10 years:

y = 34000(0.86)¹⁰ = 7524.25

The price of the car after 10 years is $7524.25 if the new car costs $34,000 and its value depreciates at 14% of its value each year.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

7 0
2 years ago
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