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Harlamova29_29 [7]
3 years ago
14

Given that Y = 2x^2-96, find x

Mathematics
1 answer:
kari74 [83]3 years ago
5 0
This isn't an equation, so you cannot "solve for x."  However, you can factor, as follows:

y = 2(x^2-49) = 2(x-7)(x+7)

If you decide to set this = to zero, then you can solve for x:  {-7, 7}.
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Solve the equation for a.<br><br> K=4a+9ab
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Answer:

a= k/4+9b

Step-by-step explanation:

hope this helps, if not let me know!

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3 years ago
I WILL MAKE WHOEVER ANSWERS THIS CORRECTLY THE BRAINLIEST :D Rei is barricading a door to stop a horde of zombies. She stacks bo
ivann1987 [24]

Answer:

See below.

Step-by-step explanation:

Well first, we need to find the weight of the table. We know that 8 boxes weighs a total of 240kg (since each box weights 30kg). Thus, we can conclude that the table weighs 70kg by doing 310-240=70.

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3 0
3 years ago
Read 2 more answers
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

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3 years ago
For the graphed exponential equation, calculate the average rate of change from x = 1 to x = 4.
zhenek [66]

Answer:

b  

Step-by-step explanation:

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