Ask question

Ask question

All categories

3 years ago

9

Dane’s puppy weighted 8 ounces when it was born. Now the puppy weighs 18 times as much as it did when it was born. How many poun

ds does Dane’s puppy weigh now?

2 answers:

viva [34]3 years ago

8 0

Just multiply 8 times 18 to get 144 then convert it into pounds which is 9 pounds

aev [14]3 years ago

3 0

144 ounces or 9 pounds.

You might be interested in

One angle of a triangle measures <img src="https://tex.z-dn.net/?f=10degrees" id="TexFormula1" title="10degrees" alt="10degrees"

iVinArrow [24]

Answer:

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

Step-by-step explanation:

Let

x ----> the measure of one angle of the triangle

y ---> the measure of the second angle

z ----> the measure of the third angle

we know that

The sum of the measure of the interior angles in any triangle must be equal to 180 degrees

$x+y+z=180^o$ -----> equation A

One angle of a triangle measures 10 degrees more than the second

$x=y+10$ ----> equation B

The measure of the third angle is twice the sum of the first two angles

$z=2(x+y)$ ---> equation C

substitute equation B in equation C

$z=2(y+10+y)$

$z=4y+20$ ----> equation D

substitute equation D and equation B in equation A

$(y+10)+y+(4y+20)=180^o$

solve for y

$6y=180-30\\6y=150\\y=25^o$

Find the value of x

$x=25+10=35^o$

Find the value of z

$z=4(25)+20=120^o$

therefore

$One\ angle: 35^o\\Second\ angle: 25^o\\Third\ angle: 120^o$

5 0

3 years ago

15x=33, what is the value of x?

DENIUS [597]

Answer:

2.2

Step-by-step explanation:

4 0

3 years ago

Teni had 16 berries. She has a number two greater than Marta. How many berries Marta had

Hitman42 [59]

I think the answer is 8
but im not 100% sure

5 0

3 years ago

Read 2 more answers

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago

Pls help I’ll mark brainliest

Lemur [1.5K]

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

7 0

3 years ago