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3 years ago

14

Find the difference. 4 and two-fifths minus 1 and seven-tenths equals what number?

2 answers:

LUCKY_DIMON [66]3 years ago

7 0

It is 2 and seven- tenths because you have to turn two-fifths into tenths to match 1 and seven-tenths so then you have 4 4/10 - 1 7/10 you have to regroup so you take 1 whole out of the 4 while equals 10 so you have 3 14/10. Then you can subtract 3 14/10 - 1 7/10 and get 2 7/10. Hope this helps:)

Varvara68 [4.7K]3 years ago

3 0

Answer:

I believe it's B or C.

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aliya0001 [1]

Circumference = pi * diameter
diameter = 8.5; pi = 3.14

C = 3.14 * 8.5
C = 26.69 in = 26.7 in

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3 years ago

Select all the distribution shaped for which the mean and median must be about the same.

irga5000 [103]

The distribution shaped for which the mean and median must be about the same will be:

D. Symmetric

E. uniform

<h3>How to illustrate the information?</h3>

In a symmetric distribution, the median is equal to the mean. The bell-shaped distribution is same as the standard normal distribution.

In a right-skewed distribution, the median is much less than the mean and a bimodal distribution is one with two modes.

Therefore, the correct options are D and E.

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2 years ago

The four-sided geometric figure pictured is called a parallelogram. One feature of parallelograms is that opposite sides have eq

Musya8 [376]

B is correct answer.

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4 years ago

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Jace gathered the data in the table. He found the approximate line of best fit to be y = –0.7x + 2.36.

finlep [7]

Answer:

the answer is:

-0.86

Step-by-step explanation:

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3 years ago

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Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le

Helen [10]

Answer: $\overline{AC}=$ 12.5

Step-by-step explanation: The triangle ABC and its altitude $\overline{BD}$ is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of $\overline{BD}$ , now we have two similar triangles, which means that ratios of corresponding sides are equal:

$\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}$

$\overline{BD}^{2}=\overline{BC}.\overline{AD}$ (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

$\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}$

$\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2}$ (2)

Substituting (2) into (1):

$\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}$

We want to find f, so:

$\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}$

$f=\frac{10^{2}-5^{2}}{10}$

f = 7.5

The length of $\overline{AC}$ is

$\overline{AC}=f+5$

$\overline{AC}=7.5+5$

$\overline{AC}=12.5$

The length of the hypotenuse of triangle ABC is 12.5 units.

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3 years ago

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