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trasher [3.6K]
3 years ago
15

Help me to solve thisssss​

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

(a + 3)

Step-by-step explanation:

a³ - 9a = a(a² - 9) = a(a + 3)(a - 3)

a² + a - 6 = (a - 2)(a + 3)

a⁴ + 27a = a(a³ + 27) = a(a - 3)(a² + 6a + 9) = a(a - 3)(a + 3)(a + 3)

HCF = (a + 3)

Hope it helps.

;)

<3

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-1.5. -1 1/2. -3/2






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HEEELP
Drupady [299]

Answer: (c)

Step-by-step explanation:

Given

f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}

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To get f\left(g(x)\right), replace x in f(x) by g(x)\ \text{i.e. by}\ \sqrt{x+5}

\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)

Using (i) and (ii)  it can be concluded that the domain of f\left(g(x)\right) is all real numbers except 0.

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