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gavmur [86]
3 years ago
7

What is the formula for strontium phosphide

Mathematics
1 answer:
Orlov [11]3 years ago
6 0
The formula for strontium phosphide is Sr3(PO4)2.

Hopefully this helps! :)
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The first option, as it positively supports the claim stated.
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3 years ago
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Please help 50 points!<br> Simplify the expressed
LenKa [72]

Answer:

Step-by-step explanation:

\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}  rewrite as multiplication

\frac{x^{2} +3x-4x-12}{x+4} * \frac{2(x^{2}-16) }{x^{2} -8x+16}  look to factor

\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}  , difference of 2 squares and perfect square

\frac{(x+3)(x-4)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}, finish factoring and simplify

2(x+3)

3 0
2 years ago
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
2 years ago
An equilateral triangle has an apothem of 5 cm. Find the perimeter of the triangle to the nearest centimeter.
san4es73 [151]
The apothem is the distance from the center to the midpoint of one of the sides of a regular polygon.  You can make a right triangle with the apothem, the line from the midpoint to the corner and the line from the center to the corner.  An equilateral triangle has 60 degree angles (180/3).  The right triangle has half of one of those angles so 30 degrees.  Now we have a 30-60-90 triangle where the short leg is 5cm.  The long leg, which is also half of one side of the triangle is thus 5\sqrt{3}.  A whole side of the triangle is 10\sqrt{3}.  Multiply that by 3 to get the perimeter of <span>30\sqrt{3}.</span>
4 0
3 years ago
Convert the fraction to a decimal. Round to the nearest thousandths.135/650 Question 3 options: .2 .20 .2076923077 .208
Lilit [14]
Turn in into a division problem :
135÷650=
About .208
5 0
2 years ago
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