Question

Researchers studying a small milkweed population note that some plants produce a toxin and other plants do not. They identify the gene responsible for toxin production. The dominant allele (T) codes for an enzyme that makes the toxin, and the recessive allele (t) codes for a nonfunctional enzyme that cannot produce the toxin. Heterozygotes produce an intermediate amount of toxin. The genotypes of all individuals in the population are determined (TT = 0.56; Tt = 0.28; tt = 0.16) and used to determine the actual allele frequencies in the population. Is this population in Hardy-Weinberg equilibrium? Calculate the T and t.
I already know the answer is "No, there are more homozygotes than expected", but I do not understand how to find this answer. SHOW WORK.

Answer 1

Answer:

when doing this dont square p or q b/c (p^2) represents homozygous frequency already same thing for q and 2pq (dont need to multiply by 2)

also to do p + q = 1

take the square root of the genotype frequencies THEN add them, if greater than one does not meet equlibrium b/c more HOMOZYGOTES than expected

as in this case

No; there are more homozygotes than expected.