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horrorfan [7]
3 years ago
6

Juanita is making paper flowers to use as decoration for a party. The table below shoes the total cost for different numbers of

flowers.
Part A: complete the table below.
Part B: write an equation and use it to find how many flowers Juanita can make if she has $14.00 to spend. Show your work.
Equation:_______juanita can make________flowers if she has $14.00 to spend.

Mathematics
2 answers:
Leno4ka [110]3 years ago
3 0

Answer:

A.

$1.40, $1.75, $2.10

B.

40

Step-by-step explanation:

A.

Follow the pattern of $0.35

B.

14 divided by 0.35 = 40

Hope this helps! Please mark as brianliest.

Whitepunk [10]3 years ago
3 0

A) The cost of 1 flower is $0.35

Multiply the number of flowers by 0.35 to get the total cost:

4 x 0.35 = $1.40

5 x 0.35 = $1.75

6 x 0.35 = $2.10

B)

Let the number of flowers = X

Multiply the cost of a flower by the number of flowers to get 0.35X

Now you need that to equal the amount she spends so you have:

EQUATION: 0.35X = 14

To find X , divide both sides by 0.35:

X = 14.00 / 0.35

X = 40 flowers.

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A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
4 years ago
After graduating from college, Jane has two job offers to consider. Job A is compensated at $100,000 a year but
vaieri [72.5K]

Answer: (a)  Job A , by approximately $69, 482

\\ (b)  Job A , by approximately $6,867

 \\(c) Job B , by approximately $ 767,362

  \\ (d) Job A

Step-by-step explanation:

JOB B

\\The starting Salary is $ 10,000

Since there is an increment of 25% at the beginning of each new year. The breakdown of the increment is as follow:

\\First year : 125% of $ 10,000 = $12,500

\\Second year : 125% of $ 12,500 = $15,625

\\Third year : 125% of $15,625= $19,531.25

\\Fourth year: 125% of $19,531.25 = $24,414.06

\\Fifth year : 125% of $24,414.06 = $30,517.58

\\Sixth year: 125% of $30,517.58 = $38,147.00

\\Seventh year: 125% of $38,147.00 = $47,683.75

\\Eight year: 125% of $47,683.75 = $59,604.69

\\Ninth year: 125% of $59,604.69 = $74,505.86

\\Tenth year: 125% of $74,505.86 = $93,132.32

\\Following the same procedure:

\\Eleventh year = $116,415.40

\\Twelfth year = $145,519.25

\\Thirteenth year = $181,899.06

\\Fourteenth year = $227,373.82

\\Fifteenth year = $ 284,217.29

\\Sixteenth year = $355,271.61

\\Seventeenth year = $444,089.51

\\Eighteenth year = $555,111.89

\\Nineteenth year = $693,889.86

\\Twentieth year = $867,362.32

\\(a) Following the analysis above, at the beginning of the fifth year Job A will have a greater annual salary

\\Difference: Salary of Job A at the beginning of fifth year remains $ 100,000 while that of Job B resulted into $ 30,517.58, the difference implies

$100,000 - $ 30,517.58 = $69,482

\\(b) At the beginning of tenth year, Job A is still $100,000, Job B resulted into $93,132.32. Job A is still greater by approximately $6,867

\\(c) At the beginning of the twentieth year, the annual salary of A is still $ 100,000 while the annual salary of B is $ 867,362.32. Job B annual salary is greater by approximately $ 767,362

\\(d) If I were in Jane’s shoe I will take Job A and work for few years to gain more experience the look for a job that pays better. Waiting for many years in case of Job B is risky , market situation is uncertainty.

8 0
4 years ago
Which graph represents the equation y = x-3?
AlekseyPX

Answer:

The first

Step-by-step explanation:

The intercept is a negative so the line will be going the opposite way

6 0
3 years ago
Read 2 more answers
HELPPPPPPPPPPPPPPPP ASAPPPP this is egit due todayyyyyy
Basile [38]
The answer is 42m+12
3 0
3 years ago
in the school cafeteria students chose their lunch from 3 sandwiches, 3 soups, 4 salads, and 2 drinks. how many different lunche
Vesna [10]

Answer:

Answer:

3

×

3

×

4

×

2

=

72

Explanation:

Let's look at the 3 sandwiches and 3 soups first and then expand the calculation. There are 9 ways I can have one of the sandwiches and 1 of the soups:

⎛

⎜

⎜

⎜

⎜

⎝

0

Soup 1

Soup 2

Soup 3

Sandwich 1

1

2

3

Sandwich 2

4

5

6

Sandwich 3

7

8

9

⎞

⎟

⎟

⎟

⎟

⎠

And so we can see that we multiply the number of sandwiches and the number of soups to get the total number of ways to get one of each.

The same works for more categories of choices, and so we multiply the 3 sandwiches, the 3 soups, 4 salads, and 2 drinks to get:

3

×

3

×

4

×

2

=

72


7 0
3 years ago
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