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marta [7]
3 years ago
10

HELPPPPPPPPPP I do not understand any of this

Mathematics
2 answers:
nikdorinn [45]3 years ago
3 0
I’m pretty sure it’s the second choice
il63 [147K]3 years ago
3 0

Answer:

I think it's the second answer

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X + 2y = 5 3x + 5y = 14 Solve the system of equations. (3, 1) (7, -1) (2, 3/2)
aniked [119]

Answer:

The solution is (3 , 1)

Step-by-step explanation:

To solve the system of the equation you can use the elimination method or substitution method.

We will use the substitution method

From the first equation x + 2y = 5⇒get  x = 5 - 2y

In the second equation 3x + 5y = 14⇒we will substitute x by 5 - 2y

3(5 - 2y) + 5y =14

15 - 6y + 5y = 14

-6y + 5y = 14 - 15

-y = -1

y = 1

Substitute the value of y in x = 5 - 2y

x = 5 - 2(1) = 5 -2 =3

∴ The solution of the system of equations is (3 , 1)

4 0
3 years ago
Read 2 more answers
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
ATTENTION WORTH 50 POINTS! I will award brainliest to whoever answers within 30 minutes and is the first answer!!! Thanks!
Nutka1998 [239]
Sweet................
a. (0,4500) initial height
b. take any to points and find slope which is rate in ft per min and is also negative in this case
c. (3,0) hits ground after 3 minutes
d. after b, use y-y1=m (x-x1) for any point (x1,y1)
ur welcome. plz follow
7 0
3 years ago
Solve for x please show work
Vanyuwa [196]

Answer:

it is 10 d a d a p a p a

Step-by-step explanation:

5 0
2 years ago
Find the value of x and y in the parallelogram. Explain.
Ray Of Light [21]

x = 26


Because 26-2=24 which would be right because it needs to equal the same size as the other side that is across from it.


y = 11


Because it’s the same size as the bottom side, which is also the side across from it.



This is true because a parallelogram has 2 sets of parallel side!!!



I hope this helps! :)

3 0
2 years ago
Read 2 more answers
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