The net ionic equation for the reaction of aluminum sulfate and sodium hydroxide
1 answer:
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5.75g
Explanation:
Given parameters:
Number of atoms = 1.505 x 10²³atoms
let us find the number of moles and mass of this atom.
Solution:
The mole is convenient unit for reporting measurements in chemistry. It allows us to make mathematical calculations:
one mole of substance contains 6.02 x 10²³atoms
Number of moles of Na given = = 0.25moles
Mass of Na atom given = number of moles x molar mass
Molar mass of Na= 23g/mole
Mass of Na = 0.25 x 23 = 5.75g
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Number of moles brainly.com/question/1841136
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Hello!
a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:
First, we have to assume that we have 100 grams of solution. This will simplify the calculations.
Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:
To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:
So, the mole fraction of NaOH is 0,073
b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:
First, we have to assume that we have 100 grams of solution. This will simplify the calculations.
Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:
Now, we apply the definition of molality to calculate the molality of the solution:
So, the molality of this solution is 4,41 m
Have a nice day!
a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:
First, we have to assume that we have 100 grams of solution. This will simplify the calculations.
Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:
To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:
So, the mole fraction of NaOH is 0,073
b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:
First, we have to assume that we have 100 grams of solution. This will simplify the calculations.
Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:
Now, we apply the definition of molality to calculate the molality of the solution:
So, the molality of this solution is 4,41 m
Have a nice day!