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Sladkaya [172]
3 years ago
14

The net ionic equation for the reaction of aluminum sulfate and sodium hydroxide

Chemistry
1 answer:
hammer [34]3 years ago
6 0
Al2so4+NaOH =Naso4+AlOH= so I think it’s B not sure
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How do conduction and convection differ?
lilavasa [31]
Conduction requires objects to have direct contact; convection does not.
5 0
3 years ago
A football player runs from the 50 yard line to the 20 in 3.4s seconds, what is his speed?
Crank

Answer:

8.8 yards per second

Explanation:

50 - 20 = 30 yards

30 yards/3.4 seconds = 8.8235

8 0
3 years ago
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Identify the strongest intermolecular force that is likely to affect each of the samples described below.
Delvig [45]

Answer:

London dispersion forces

Explanation:

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3 years ago
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Consider the following reaction at equilibrium. What will happen if FeS2 is added to the reaction? 4FeS2(s) + 11O2(g) ⇌ 2Fe2O3
aivan3 [116]

 4FeS₂ + 11O₂ →  2Fe₂O₃  +8SO₂

What  happen  if  FeS₂  is added  to the reaction  is that

The reaction will shift  in the direction  of the products


<u><em>Explanation</em></u>

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  • When  more  of reactant  added  to  a system at equilibrium,    it increases the concentration  of  reactant molecules.
  • According to collision theory,this  increase   the number of collisions per second  of reactant  molecule  and therefore more product is formed.
5 0
4 years ago
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The free energy obtained from the oxidation (reaction with oxygen) of glucose (C6H12O6) to form carbon dioxide and water can be
babunello [35]

Answer:

The correct answer is -2878 kJ/mol.

Explanation:

The reaction that takes place at the time of the oxidation of glucose is,  

C₆H₁₂O₆ (s) + 6O₂ (g) ⇒ 6CO₂ (g) + 6H₂O (l)

The standard free energy change for the oxidation of glucose can be determined by using the formula,  

ΔG°rxn = ∑nΔG°f (products) - ∑nΔG°f (reactants)

The ΔG°f for glucose is -910.56 kJ/mol, for oxygen is 0 kJ/mol, for H2O -237.14 kJ/mol and for CO2 is -394.39 kJ/mol.  

Therefore, ΔG°rxn = 6 (-237.14) + 6 (-394.39) - (-910.56)

ΔG°rxn = -2878 kJ/mol

8 0
3 years ago
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