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3 years ago

The product of six and a number is multiplied by nine

Mathematics

2 answers:

alex41 [277]3 years ago

5 0

6 + y × 9 (the x is a times sign btw)

sdas [7]3 years ago

5 0

I am not sure if this is what you mean but here you go. I hope I helped you.

b X 6= n *9

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A garden is 4 yards 24 in wide and seven yards write the ratio of width to the length as a fraction in simple form

Serjik [45]

The question is written unclear.
my guess would be 24:7 (24/7)

5 0

4 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago

PLEASE HELP I WILL BRAINLIST

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

Since they intersect you can just solve for x and y

since y=-4x and y=x^2+2x+8, you can set -4x=x^2+2x+8

add 4x to both sides to make 0=x^2+6x+8

and factor out (x+4)(x+2)

so the solutions for x are -4 and -2

then insert the two values for x into the first equation

so y=-4(-4) and y=-4(-2)

so y=16 and y=8 when x=-4 and x=-2

so the smallest value for y in both equations is 8

Please give brainliest :)

3 0

3 years ago

Put the following numbers in order from least to greatest 2/10 2/9 1/4 .01 .21

padilas [110]

.01 2/10 .21 2/9 1/4

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3 years ago

What is the common denominator of 4/12

Tema [17]

Answer:

lcm of

Step-by-step explanation:

it is 12and 2.........

5 0

3 years ago