Answer:First three terms: 11,20,29 .
Step-by-step explanation:
Write a systems of equations. tn=a+(n−1)d. sn=n2 (2a+(n−1)d). So,. 110=11+(n−1)d 726=n2(22+(n−1)d).
I hope this is right
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
I believe the answer is B because you multiply 18 and 40 then subtract 320 from that and you will 400.