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3 years ago

A ray is a defined term because it ?

1 answer:

8 0

A ray is a defined term because it has no width or depth is described using an undefined term has an informal definition travels forever in one way

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Will mark bianleast

Galina-37 [17]

Left 7 units and up 3 units

8 0

3 years ago

Read 2 more answers

Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B

jeka94

$\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0$

$M_y=35x^4+14x^5-6y^2-12xy^2$
$N_x=35x^4-6y^2$

$\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2$

This suggests an integrating factor depending on $x$ only is possible, and given by

$\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}$

Distributing across the ODE, we end up with

$\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0$

The equation is now exact, with

${M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}$

Now we find the solution:

$F_x=M^*$
$F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx$
$F=(7x^5y-2xy^3)e^{2x}+f(y)$

$F_y=N^*$
$(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}$
$f'(y)=0$
$\implies f(y)=C$

The general solution is then

$F(x,y)=(7x^5y-2xy^3)e^{2x}=C$

7 0

4 years ago

Which of the systems of equations below is equivalent to the system shown?

amm1812

Answer:

$D.....is\: the \: equivalent \: system$

Step-by-step explanation:

$if \to 4x + 5y = 3 \\ if \to 2x + 3y = 1 \\then \\ 2 \times \: 4x + 5y = 3 \\ 4 \times 2x + 3y = 1 \\ 10y - 12y = 6 - 4 \\ - 2y = 2 \\ \boxed{ y = - 1} \\ 4x + 5y = 3 \\ 4x +5( - 1) = 3 \\ 4x - 5 = 3 \\ 4x = 3 + 5 \\ 4x = 8 \\ \boxed{x = 2} \\ hence \: the \: equivalent \: system \: is \to D \\$

7 0

3 years ago

Question 1 (1 point)

svlad2 [7]

Answer:

9π units²

Step-by-step explanation:

To obtain an exact answer, use π, not an approximation such as 3.14.

A = πr² is the appropriate formula.

Here,

A = (3)^2·π units², or 9π units²

8 0

3 years ago

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The range of the function?<br> 1 2 <br> 2 4<br> 3 9<br> 4 16

wariber [46]

Answer:

2,4,9,16

Step-by-step explanation:

are range because they are exactly opposite of domain

6 0

2 years ago