Given:
The sequence is -8, -12, -16.
To find:
The nth and 52th term of the given sequence.
Solution:
We have,
-8, -12, -16
It is an AP because the difference between consecutive terms are equal. Here, first term is -8 and the common difference is
The nth term of an AP is
Where, a is first term and d is common difference.
Putting a=-8 and d=-4, we get
Putting n=52, we get
Therefore, the equation for the nth term of the given sequence is and the 52nd term of the sequence is -212.
Let x,x+2,x+4,x+6 be 4 consecutive no then,
sum of first 3 no=4x+12
According to condition,
20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd
5(x+6)-20=4+(sum of first 3 no)
5(x+6)-20=4+(4x+12)
5(x+6)-20=4x+16
5x+30-20=4x+16
5x+10=4x+16
5x-4x=16-10
x=6
So,
1st no=x=6
2nd no=x+2=8
3rd no=x+4=6+4=10
4th no=x+6=6+6=12
You start off,
16 x 2 = 32
You're looking for x so,
49 - 32 = 17
Hope this helps :)!
Brainliest please
I think the answer is i D hope this helps
