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3 years ago

Alex was trying to guess the month of her brother's birthday? She knew that the

Mathematics

2 answers:

sertanlavr [38]3 years ago

6 0

Answer:

33.3%

Step-by-step explanation:

out of all 12 months, there are 3 months with J, January, June, July

100/3=33%

Pachacha [2.7K]3 years ago

3 0

Answer:

16.67

Step-by-step explanation:

2/12

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Please Help). Use the figure below to answer the questions. A) Describe in words a sequenc of transformations that maps □ABC to

lesya [120]

Answer:

See below

Step-by-step explanation:

The initial ordered-pairs are $(x, y)$

We have a rotation of 90 degrees counterclockwise with respect to origin

Note. Previously the points were

$A(-3, 4), B(-3, 0), C(-1, 3)$

After the rotation, we have

$A(-4, -3), B(0, -3), C(-3, -1)$

Thus, $(x, y) \rightarrow (-y, x)$

Then shifting horizontally to the right 2 units, we get ΔA'B'C'

Thus,

$(x, y) \rightarrow (-y, x) \rightarrow (x+2, y)$

7 0

3 years ago

What is the value of yearly compensation package that includes $65,000 salary the forecast of a $350 Dollar per month health ins

Klio2033 [76]

Answer:

$69560

Step-by-step explanation:

The yearly compensation package includes a yearly salary of $65000, the health insurance plan of $350 per month and a life insurance premium of $30 per month.

Total compensation in health insurance plan is $(350 × 12) = $4200

Total compensation in life insurance premium is $(30 × 12) = $360

Therefore, total yearly compensation package is $(65000 + 4200 + 360) = $69560 (Answer)

4 0

3 years ago

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$