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horrorfan [7]
4 years ago
6

Sodium fluoride (naf), sodium fluorosilicate (na2sif6), and fluorosilicic acid (h2sif6) are commercially available in 100.0-lb c

ontainers. calculate the mass, in kg, of fluoride ion (f−) in a 100.0-lb container for each of these three compounds. express the masses in kilograms to two significant figures separated by commas.
Chemistry
1 answer:
nekit [7.7K]4 years ago
6 0

First let us identify the molar masses:

NaF = 42 g/mol = 42 lb/lbmol

Na2SiF6 = 188 g/mol = 188 lb/lbmol

H2SiF6 = 144 g/mol = 144 lb/lbmol

F = 19 g/mol

 

There is 1 F in every NaF, 6 F in every Na2SiF, and also 6 F in every H2SiF6. Therefore:

F in NaF = (100 / 42) * 1 * 19 = 45.23 lb = 21 kg

F in Na2SiF6 = (100 / 188) * 6 * 19 = 60.64 lb = 28 kg

<span>F in H2SiF6 = (100 / 144) * 6 * 19 = 79.17 lb = 36 kg</span>

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