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Korolek [52]
4 years ago
13

What mineral is used to create iron ore

Chemistry
1 answer:
Sav [38]4 years ago
8 0
It would be gold ...................
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What is the name for the compound li2so4
Mariana [72]

Answer:

Explanation:

Lithium Sulphate

6 0
3 years ago
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Ionic compounds can conduct electricity when dissolved in water or melted, because
emmainna [20.7K]
I believe the correct response would be A. The ions once dissolved in the solution are free to move
5 0
4 years ago
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what type of structural isomerism arises when a particular ligand is capable of coordinating to a metal in two ways?
aivan3 [116]

The type of structural isomerism arises when a particular ligand is capable of coordinating to a metal in two ways is linkage isomer.

<h3>What are structural isomerism?</h3>

Structural isomerism is a kind of isomerism in which molecular formula of the compound is same but they all have different arrangement of atoms or bonding in them.

If in any compound particular ligand is attached to the metal through different sides of the compound, then the product which is formed by these arrangement is known as linkage isomers.

Example of the linkage isomer is attached below.

Hence, the required isomerism is linkage isomerism.

To know more about structural isomerism, visit the below link:
brainly.com/question/15183293

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6 0
2 years ago
What will happen to the temperature of a substance if the kinetic energy of the molecules decreases?
V125BC [204]
The temperature decreases
8 0
4 years ago
As the weak acid (HA) is titrated with a strong base (OH−), the neutralization reaction is:
andrey2020 [161]

Answer:

a) [HA] = 0.012 M; [A-] = 4 E-3 M

b) pH = 3.47

Explanation:

neutralization reaction:

  • HA + OH- → A- + H2O

∴ mol HA = 0.0015 mol

∴ mol A- = 0.0005 mol

∴ Vsln = 125 mL = 0.125 L

a) approx. concentration:

⇒ [HA] = 0.0015 mol / 0.125 L = 0.012 mol/L

⇒ [A-] = 0.0005 mol / 0.125 L = 4 E-3 mol/L

b) pH = ?

∴ pKa = 3.90 = - Log Ka

⇒ Ka = 1.26 E-4 = ([H3O+]*( 4 E-3 + [H3O+])) / (0.012 - [H3O+])

⇒ 1.512 E-6 - 1.26 E-4[H3O+] = 4 E-3[H3O+] + [H3O+]²

⇒ [H3O+]² + 4.126 E-3[H3O+] - 1.512 E-6 = 0

⇒ [H3O+] = 3.3866 E-4 M

⇒ pH = 3.4702

8 0
4 years ago
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