What concentration of OH is required to created a pOH of 1.3.

Helga [31]

Answer:

They all vibrate, but they all move differently.

Explanation:

Similarities: They all consist of particles and vibrate, just at different frequencies.

Differences: The particles in solids move slowly and vibrate. In liquids, they move a bit quicker and slide past one another. They will also take the shape of the container they're in. In gases, they move freely at high speeds and also taking the shape of the container.

Hope this helped! :)

3 0

4 years ago

What are the two homologous structures?

photoshop1234 [79]

analogous and homologous

4 0

4 years ago

An analysis of a 4.2-gram sample of a compound is found to contain 54.76 percent sodium (Na) and 45.24 percent fluorine (F). De

Dvinal [7]

The answer to this question is:

An analysis of a 4.2-gram sample of a compound is found to contain 54.76 percent sodium (Na) and 45.24 percent fluorine (F). Determine the empirical formula of the compound?.
"NaF"

Hoped This Helped, Hgibore
Your Welcome :)

6 0

3 years ago

Read 2 more answers

A 55.0-kg skydiver free falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a ve

morpeh [17]

The kinetic energy of a moving object is calculated through the equation,
KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity. Substituting the known values in the problem above,
KE = 0.5(55 kg)(16 m/s)²
KE = 7,040 J
Thus, the kinetic energy of the skydiver is approximately equal to 7 kJ.

4 0

3 years ago

Read 2 more answers

"Thermite" reactions have been used for welding metal parts such as railway rails and in metal refining. One such thermite react

frosja888 [35]

Answer: The given reaction is non-spontaneous in nature.

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$3Mg(s)+Cr_2O_3(s)\rightarrow 3MgO(s)+2Cr(s)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(3\times \Delta S^o_{(MgO(s))})+(2\times \Delta S^o_{(Cr(s))})]-[(3\times \Delta S^o_{(Mg(s))})+(1\times \Delta S^o_{(Cr_2O_3(s))})]$

We are given:

$\Delta S^o_{(Mg(s))}=32.68J/K.mol\\\Delta S^o_{(Cr_2O_3(s))}=81.2J/K.mol\\\Delta S^o_{(MgO(s))}=26.94J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(3\times (26.94))+(2\times (23.77))]-[(3\times (32.68))+(1\times (81.2))]\\\\\Delta S^o_{rxn}=-50.88J/K=-0.0509kJ/K.mol$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

To calculate the standard Gibbs free energy of the reaction, we use the equation:

$\Delta G^o=\Delta H^o-T\Delta S^o$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

$\Delta H^o$ = standard enthalpy change of the reaction = 665.1 kJ/mol

T = Temperature = 298.15 K

$\Delta S^o$ = standard entropy change of the reaction = -0.0509 kJ/K.mol

Putting values in above equation, we get:

$\Delta G^o=(665.1kJ/mol)-(298.15K\times (-0.0509kJ/K.mol))=680.27kJ/mol$

As, the Gibbs free energy of the reaction is coming out to be positive, the reaction is non-spontaneous in nature.

Hence, the given reaction is non-spontaneous in nature.

4 0

4 years ago