Question

3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and the density of lead is 11.3 g/cm3, what is the mass of the apron in grams?

Answer 1

Answer:

4.67 kg

Explanation:

Given data

• Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm

• Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.

$V = 75.0 cm \times 55.0 cm \times 0.10 cm = 413 cm^{3}$

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.

$\rho = \frac{m}{V} \\m = \rho \times V = \frac{11.3g}{cm^{3} } \times 413cm^{3} = 4.67 \times 10^{3} g = 4.67 kg$