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Dafna1 [17]
2 years ago
11

What is 783 divided by 18

Mathematics
2 answers:
AURORKA [14]2 years ago
5 0
783÷18= 43.5
it equals 43.5
alukav5142 [94]2 years ago
4 0
43.5 is 783 divided by 18      783 ÷ 18 = 43.5
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Brilliant_brown [7]
Graph A because the slope and y intercept is correct on that graph
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What is the measure, in degrees, of ABC? <br>​
kirza4 [7]

Answer:

25 Degrees

Step-by-step explanation:

155+25=180

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2 years ago
What is -15x=0 solution
cricket20 [7]
Here is the method for solving that equation:

Step #1:  Write the equation:

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Step #2:  Divide each side of the equation by -15 :

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3 years ago
In ¾ pound of a banana bread, there is ½ cup of cinnamon. How much cinnamon does the bread contain per pound?
Shkiper50 [21]

1 pound of bread contains \frac{2}{3} cups of cinnamon.

<h3><u>Solution:</u></h3>

Given that , In \frac{3}{4} pound of a banana bread, there is \frac{1}{2} cup of cinnamon

<em><u>To find:</u></em>

Amount of cinnamon per pound in bread

Let "n" be the cinnamon per pound present in bread

\frac{3}{4} pound of banana bread ⇒ \frac{1}{2} cup of cinnamon

Then, 1 pound of bread ⇒ n cups of cinnamon

Now, let us use criss cross method (i.e. multiplying the diagonal ordered terms and equating them)

\begin{array}{l}{\rightarrow n \times \frac{3}{4}=\frac{1}{2} \times 1} \\\\ {\rightarrow n \times \frac{3}{4}=\frac{1}{2}} \\\\ {\rightarrow n=\frac{1}{2} \times \frac{4}{3}} \\\\ {\rightarrow n=\frac{2}{3}}\end{array}

Hence, 1 pound of bread contains \frac{2}{3} cups of cinnamon.

3 0
3 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
2 years ago
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