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den301095 [7]
3 years ago
6

I don't know how to solve this problem

Mathematics
2 answers:
defon3 years ago
4 0
Divide 180 by 5 to get A-36
elixir [45]3 years ago
4 0

Answer:

giibgbt I eh r no u vfjud. Viv

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The perimeter of a pool table is 30 feet. The table is twice as long as it is wide. What is the length of the pool table?
olga55 [171]

So, 30 is the perimeter. We are told the table is twice as long as it is wide.

So, we have think of 2 numbers, one being twice as big than the other. So, it is a rectangle The two number represents the length and the width. To find the perimeter we add all the lengths and the widths. Since the pool table is a rectangle we have two lengths and two widths.

So,

the tow numbers be 10 and 5. 5 is half of 10 and, when multiplied by 2 it is 10. So just to make sure the numbers 5 and 10 work out lets do a calculation.

So,

10+5+10+5 = 30feet. This proves that the sides are these two numbers.  

8 0
3 years ago
1) 2678 cm into feet.
strojnjashka [21]
Set up multiplication/division of proportions to cancel out units that you don't want and to introduce units that you do want in your final solution...

2678cm(in/2.54cm)(ft/12in)=2678/30.48 ft≈87.86 ft  (to nearest hundredth)
6 0
3 years ago
Read 2 more answers
The measure of two complementary angles are in the ratio 1:4. What are the degree measures of the two angles ?
777dan777 [17]

Answer:

18,72

Step-by-step explanation:

Complementary angles add to 90 degrees

Multiply the ratio by x

1x+4x = 90

Combine like terms

5x = 90

divide by 5

5x/5 = 90/5

x =18

The first angle is 18 degrees

4*18 =72

The second angle is 72 degrees

7 0
3 years ago
Coach Kelly brought 28 L of water to the
Leviafan [203]

Answer:

Step-by-step explanation:

it one times one pllus the 100 blus thewendy

4 0
2 years ago
Quadratic Equations<br> How do I solve a quadratic equation?
malfutka [58]
There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
 ex:        x^2+ 4x + 3 =0
             (x+3) (x+1) = 0
              x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)

2) The other way to solve a quadratic function is by using a formula:
    given: ax^2 +bx +c=0
    x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
    
 ex: 3x^2 + 4x -2=0
    x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
                                                        and
                                              x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
5 0
3 years ago
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