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erma4kov [3.2K]
3 years ago
7

Fatima paid for 5 pallets of grass to be delivered.

Mathematics
2 answers:
Sophie [7]3 years ago
3 0
The answer is A
5 x 129.95 = 649.75
649.75 + 76.20 = 725.95
Deffense [45]3 years ago
3 0
A 725.95 is the most reasonable answer
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Which number has a 3 with a value that is 100 times greater than the value of 3 in 20.342 ?
Elodia [21]

Answer:

You didnt give any options, but I'm guessing one of them has a 3 in the tens digits, which should be the right answer.

Step-by-step explanation:

4 0
3 years ago
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If there is thirtysix times it by 1 million how much will that be
alexira [117]

Answer:

36*1 000 000

=36  000   000

Step-by-step explanation:

8 0
3 years ago
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A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

3 0
3 years ago
On Thursday a local shop sold a combination of 417 hamburgers and cheese burgers. The number of cheeseburgers sold was two times
seropon [69]

Answer:

The number of hamburgers sold was 139 and the number of cheeseburgers  sold was 278.

Step-by-step explanation:

Let

x -----> the numbers of hamburgers sold on Thursday

y -----> the numbers of cheeseburgers sold on Thursday

we know that

x+y=417 ----> equation A

y=2x ----> equation B

Substitute the equation B in equation A and solve for x

x+2x=417

3x=417

x=139

Find the value of y

y=2(139)=278

therefore        

The number of hamburgers sold was 139 and the number of cheeseburgers  sold was 278.

8 0
3 years ago
Bryson buys a bag of 64 plastic miniature dinosaur s. Could he distribute them equally into six storage containers and not have
Burka [1]
No because 6 multiplied by 10 is 60 and 6 multiplied by 11 is 66
8 0
4 years ago
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