It would not pass under the bridge because ig you divide 162 by 12 it would equal 13.5
Answer:
42 times
Step-by-step explanation:
Since there are 6 sides on a fair dice, each having a number 1 thru 6 with no numbers repeating and half those numbers being odd, Bridget can expect to roll an odd number 84*(1/2) times. So our answer is 42.
Also, if you could please mark this "brainliest" (the crown) it would help a lot!
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Answer:
x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)
Step-by-step explanation:
Solve for x:
x^3 = -125
Taking cube roots gives 5 (-1)^(1/3) times the third roots of unity:
Answer: x = -5 or x = 5 (-1)^(1/3) or x = -5 (-1)^(2/3)
<span>2257987 is the answer</span>