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vfiekz [6]
3 years ago
9

EASY QUESTION FOR 20 POINTS! HELPPP !

Mathematics
2 answers:
galben [10]3 years ago
7 0

Step-by-step explanation:

numbers at the block's side multiple by two.Or numbers at the minute's side divide by two.

Elina [12.6K]3 years ago
4 0

Answer: divided by 2

Step-by-step explanation:

You might be interested in
Writing unit fractions to add or subtract.
Ivahew [28]

1/3 + 1/6

---Find a common denominator, or the least common multiple of the given denominators. In this case, that would be 6.

1/3 = 2/6

1/6 = 1/6

---Now add the fractions

2/6 + 1/6

3/6

---Simplify/Reduce the fraction

3/6

1/2

Answer: 1/2

1/3 + 1/6 = 2/6 + 1/6 = 3/6 (or 1/2)

Hope this helps!

3 0
2 years ago
Read 2 more answers
Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

8 0
3 years ago
Larry’s family made a donation to the library. His mom gave half as much as larry. His dad gave 5 times as much as Larry’s siste
storchak [24]

Answer:

The family donated $52.50

Step-by-step explanation:

Larry's mom donated $7.50 ($15 ÷ $2=$7.50)

Larry's dad donated $25.00 ($5 x $5=$25.00)

Larry's sister donated $5.00 ($15 - $10=$5.00)

Larry donated $15.00

6 0
3 years ago
If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?
Alisiya [41]
If k is odd, then

\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor

while if k is even, then the sum would be

\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4

The latter case is easier to solve:

\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0

which means k=6.

In the odd case, instead of considering the above equation we can consider the partial sums. If k is odd, then the sum of the even integers between 1 and k would be

S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)

Now consider the partial sum up to the second-to-last term,

S^*=2+4+6+\cdots+(k-5)+(k-3)

Subtracting this from the previous partial sum, we have

S-S^*=k-1

We're given that the sums must add to 2k, which means

S=2k
S^*=2(k-2)

But taking the differences now yields

S-S^*=2k-2(k-2)=4

and there is only one k for which k-1=4; namely, k=5. However, the sum of the even integers between 1 and 5 is 2+4=6, whereas 2k=10\neq6. So there are no solutions to this over the odd integers.
5 0
3 years ago
Simplify<br> 6^7 /6^5<br> leaving your answer in index form.
Agata [3.3K]

Answer:

36

Step-by-step explanation:

5 0
3 years ago
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