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4 years ago

8p-5(p+3)=(7p-1)3 Please I really need help on this

Mathematics

2 answers:

4vir4ik [10]4 years ago

8 0

The answer is p= 4.25

pav-90 [236]4 years ago

3 0

8p-5(p+3)=3(7p-1)
8p-5p-15=21p-3
3p-15=21p-3
-3p on both sides
-15=18p-3
+3 on both sides
-12=18p
/18 on both sides
p= -12/18 or p=0.66..

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A softball team is ordering pizza to eat after their tournament. They plan to order cheese pizzas that cost $ 6 each and four-to

Vlada [557]

Answer:

6x + 10t

Step-by-step explanation:

We know that each cheese pizza (c) is $6, and each four topping pizza (f) is $10.

Knowing this, the total of all the pizzas is going to be 6* the amount of cheese (c) plus 10* the amount of four-toppings.

6x + 10t

8 0

3 years ago

Pick the correct answer :)

amm1812

= 3a^2b(cuberoot(b^2)) - 3a^2b^3(square root(3a))

answer is the first choice

4 0

3 years ago

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe

lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = $\frac{(length-covered-by-49-cars)}{Number-of-cars}$

= $\frac{528}{49}=10.78$

Therefore, the average length of car is 10.78 feet

6 0

3 years ago

The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in

Stolb23 [73]

Answer:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=34.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=300-1=299$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that $t_{\alpha/2}=1.653$

And the margin of error is given by:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

4 0

3 years ago

Read 2 more answers

Los divisores de 100 son tambien divisores de 50 ?

sergiy2304 [10]

Answer:

La afirmación es falsa, no todos los divisores de 100 son divisores de 50, ya que solo se toman en cuenta sus divisores comunes, los cuales son todos los divisores de 50. Expresamos a 100 en sus factores primos: 100 = 2 · 2 · 5 · 5 = 2² · 5² Divisores de 100: {1, 2, 4, 5, 10, 20, 25, 50, 100}

Step-by-step explanation:

8 0

3 years ago