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ZanzabumX [31]
3 years ago
13

You work as a sales clerk at a fashion boutique. The store is having a 20 percent off everything sale. Additionally, your manage

r wants you to mark down a stack of jeans from the sale price by 20 percent more. The original cost of the jeans is $30.00, and you calculate the final sale price to be $18.00.
Your Calculation:

30.00 × [1 − (0.20 + 0.20)]
30.00 × 0.60
18.00

Is there a mistake in the calculation? If so, Identify the mistake.
A) yes, added 20% offs
B) yes, a subtraction mistake
C) yes, a multiplication mistake
D) no mistake, the calculation is correct
E) yes, a decimal placement error
Mathematics
2 answers:
lubasha [3.4K]3 years ago
7 0

Your answer is D.


The jeans are 40% off (because you add 20% more).

And the original cost of the jeans is $30.


You could have done:

30 · 0.40 = 12  (Find 40% of $30, then subtract 30 by 40% of 30 to get the new sale price]

30 - 12 = 18


1 - 0.40 = 0.60  (You subtract 1 by 0.40 to get 0.60, which is the % of the original price that you have to pay)

30 · 0.60 = 18

drek231 [11]3 years ago
5 0

Answer:

A.)yes, added 20% offs

Step-by-step explanation:

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If Rupert does all his math quizzes, and if he scores 4 correct for every 5 questions, what will his percentage correct be?
Sauron [17]

Answer:

LOL IT'S GONNA BE 80%

Step-by-step explanation:

HOPE THIS HELPS, SORRY FOR ALL THE CAPS

5 0
2 years ago
three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are
goldenfox [79]
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure

6 0
3 years ago
Read 2 more answers
Which equation could have been used to create this graph?
andrew11 [14]
The answer is A hope this helps 
4 0
3 years ago
Why does a y-intercept not count as a zero?
Genrish500 [490]

Answer:

It only counts as a zero when the y-intercept is (0,0).

Step-by-step explanation:

The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.

7 0
3 years ago
How o I get the awnser to 9s+3=57 I need help asap im in 8th grade
PIT_PIT [208]
First subtract 3 from both sides of the equal sign. 
9s + 3 = 57
      - 3     -3
9s = 54

Then divide both sides by 9.
9s = 54
/9     /9
s = 6

You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6  + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)

Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations. 
3 0
3 years ago
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