Answer:
LOL IT'S GONNA BE 80%
Step-by-step explanation:
HOPE THIS HELPS, SORRY FOR ALL THE CAPS
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure
The answer is A hope this helps
Answer:
It only counts as a zero when the y-intercept is (0,0).
Step-by-step explanation:
The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.
First subtract 3 from both sides of the equal sign.
9s + 3 = 57
- 3 -3
9s = 54
Then divide both sides by 9.
9s = 54
/9 /9
s = 6
You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6 + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)
Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations.