Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
The right answer for the question that is being asked and shown above is that: "13 ft."An iron tank is constructed in the form of an isosceles trapezoid. Each base angle measures 105°, the length of the base is 10 feet, and each of the <span>nonparallel sides is 12 feet long. The length of a diagonal brace to the nearest whole number is 13 ft</span>
First you would divide 45 by 9 to see how many times it will double which gives you 5. Then, you would multiply 2000 by 2^5 (or just 2000x2x2x2x2x2) to get $64000
Answer:
Step-by-step explanation:
To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:
![A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%261%261%261%5C%5C3%267%26-1%261%5Cend%7Barray%7D%5Cright%5D)
And the vector B is formed with the solution of each equation of the system:![b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C-3%5C%5C6%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called 
.
![A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%266%261%261%5C%5C3%261%26-1%261%5Cend%7Barray%7D%5Cright%5D)
The value of y using Cramer's rule is:
Find the value of the determinant of each matrix, and divide:
The top two answers are equivalent, while the bottom one is not. You would use distributive property in the parentheses. If both expressions are the same, they are equivalent
