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kicyunya [14]
3 years ago
6

Alan had already read 12 books this year before joining a book club, and he plans to read 1

Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Respuesta:

Step-by-step explanation:

7 libros

12 - 19 ⇒ 7

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3.2 cm on the map correspond to 4 km in the actual distance?
geniusboy [140]

Answer:

Step-by-step explanation:

Here, 3.2 centimeters on the map is equivalent to 4 kilometers. We can use unitary method to find, how many kilometer/kilometers each centimeter corresponds to. Using the unitary method: Therefore, the scale of map represents 1.25 kilometers for each centimeter.

6 0
4 years ago
Multiply.<br> Write your answer in simplest form.<br> Help me plz
damaskus [11]
(-5/3)•(-6/1)=(30/3)
(30/3) simplified is (10/1)
3 0
3 years ago
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The perimeter of the base of a regular quadrilateral prism is 60 cm, the area of a lateral face is 105 cm2. Find: the volume of
Harman [31]
Since the base is a regular quadrilateral, each of its 4 sides must have length
  s = P/4
  s = (60 cm)/4 = 15 cm

The area of one lateral face is the product of side length and height.
  A = s×h
  105 cm² = (15 cm)×h
Then the height of the prism is
  h = (105 cm²)/(15 cm) = 7 cm

The area of the base is then
  B = s²
  B = (15 cm)² = 225 cm²

The volume of the prism is the product of its base area and height.
  V = Bh
  V = (225 cm²)×(7 cm) = 1575 cm³


The volume is 1575 cm³.
5 0
3 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

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3 years ago
A biased coin with P({head})=0.6 is tossed three times. Let the binomial random variable X represent the number of heads obtaine
Angelina_Jolie [31]

Answer:

The sketch is carried out and the probabilities are calculated.

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3 years ago
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