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nata0808 [166]
3 years ago
6

Six times a number +4 is the same as the number -11

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0
6x+4=-11
6x=-15
X=-15/6
X=-2.5
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Sasha sells T-shirts. Each day she earns a set amount, plus a commission.
WARRIOR [948]

Answer:

Domain → 0 < x < 5

Step-by-step explanation:

Sasha sells T-shirts and earns a fixed amount plus a commission by selling each shirt. (As given in the table)

Table attached shows a linear function (A regular increase in total pay with the increase in number of shirts sold)

So the input values of the table (Number of shirts sold) will represent the domain of the linear function.

Hence, reasonable domain for the function will be → 0 < x < 5

5 0
3 years ago
2. P(-4, 2), (6, 4), R(11, -2), S(2, -3)<br><br> is this is parallelogram or not??
blondinia [14]
Yes that is a parallelogram
6 0
3 years ago
En un paralelogramo de tiene ?
soldi70 [24.7K]

Answer:

Elementos y propiedades del paralelogramo

Lados: el paralelogramo tiene cuatro lados, siendo iguales y paralelos dos a dos (a y b). Ángulos: los ángulos interiores son iguales dos a dos, siendo iguales los ángulos no consecutivos (α y β). Como en todo cuadrilátero, sus ángulos interiores suman 360° (2α + 2β = 360°)

Step-by-step explanation:

Elements and properties of the parallelogram

Sides: the parallelogram has four sides, two by two (a and b) being equal and parallel. Angles: the interior angles are equal two by two, the non-consecutive angles (α and β) being equal. As in any quadrilateral, its interior angles add up to 360 ° (2α + 2β = 360 °) (English version lol)

6 0
3 years ago
What is the best way to solve integers ​
nignag [31]

Answer:

An integer is never a fraction, decimal, or percentage, it can only be a whole number. To solve integers and use their properties, learn to use addition and subtraction properties and use multiplication properties. Method 1 Using Addition and Subtraction Properties

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

Then the resulting ODE in v(x) is separable, with

1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx

On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

1-v^2=e^{2x+C}

v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
3 years ago
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