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Vikki [24]
3 years ago
7

Can someone please answer this for me it's for a homework assignment.

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0
Slope as an (improper fraction)-9/7, it can’t be simplified
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Geometry questions....help me someone please
AlekseyPX

Answer:

Triangle 1: x = 80 degrees, acute

Triangle 2: x = 10 degrees, right

Step-by-step explanation:

Triangle 1:

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation:

60 + 40 +x = 180

Solve for x:

100 + x = 180\\x = 80

So, x = 80 degrees

Because all the angles are less than 90 degrees, this is an acute triangle.

Triangle 2:

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation (with the right angle given):

3x + 60 + 90 = 180

Solve for x:

3x + 150 = 180\\3x = 30\\x = 10

So, x = 10 degrees

Because there is an angle measuring 90 degrees, this is a right triangle.

8 0
1 year ago
Read 2 more answers
6. Find the perimeter of the figure below
liraira [26]

Answer:

26 in.

Step-by-step explanation:

» <u>Concepts</u>

The perimeter for a shape is the total distance around it measured in units. The formula to find the perimeter of a trapezoid is a + b + c + d, where a & b are the bases, and c & d are the lengths of the other sides.

» <u>Solution</u>

Adding up all the sides, we get:

  • 11+7+4+4
  • 18+4+4
  • 22+4
  • 26

26 inches

3 0
2 years ago
Charlie has 32 cats, which is 8 times as many cats as Waylon. How many cats does Waylon have?
olya-2409 [2.1K]
You have to do 32 divided by 8
6 0
2 years ago
Read 2 more answers
Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4
dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

x_1\ =\ -2

y_1\ =\ 3

z_1\ =\ -4

Distance is measure across the line

\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}

So, we can write

\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k

=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k

=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k

=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3

=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18

=>18k-24+12k+9+10k-32\ =\ 18

=>\ k\ =\dfrac{13}{8}

So,

x\ =\ 3k-4

   =\ 3\times \dfrac{13}{8}-4

   =\ \dfrac{7}{4}

y\ =\ \dfrac{4k+3}{2}

   =\ \dfrac{4\times \dfrac{13}{8}+3}{2}

   =\ \dfrac{19}{4}

z\ =\ \dfrac{5k-16}{3}

  =\ \dfrac{5\times \dfrac{13}{8}-16}{3}

   =\ \dfrac{-21}{8}

Now, the distance of point from the plane is given by,

d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}

   =\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}

   =\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}

   =\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}

   =\ \sqrt{\dfrac{1177}{64}}

   =\ 4.28

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

            = 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0
3 years ago
What is the square root of 73 to the nearest hundredth?
iogann1982 [59]
Sqrt 73 = 8.54 (thats rounded to nearest hundredth)
8 0
3 years ago
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