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3 years ago

7

Can someone please answer this for me it's for a homework assignment.

1 answer:

Ulleksa [173]3 years ago

5 0

Slope as an (improper fraction)-9/7, it can’t be simplified

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Geometry questions....help me someone please

AlekseyPX

Answer:

Triangle 1: x = 80 degrees, acute

Triangle 2: x = 10 degrees, right

Step-by-step explanation:

Triangle 1:

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation:

$60 + 40 +x = 180$

Solve for x:

$100 + x = 180\\x = 80$

So, x = 80 degrees

Because all the angles are less than 90 degrees, this is an acute triangle.

Triangle 2:

By the Sum of Interior Angles Theorem, all the angles inside the triangle adds up to 180 degrees. So, set up this equation (with the right angle given):

$3x + 60 + 90 = 180$

Solve for x:

$3x + 150 = 180\\3x = 30\\x = 10$

So, x = 10 degrees

Because there is an angle measuring 90 degrees, this is a right triangle.

8 0

1 year ago

Read 2 more answers

6. Find the perimeter of the figure below

liraira [26]

Answer:

26 in.

Step-by-step explanation:

» <u>Concepts</u>

The perimeter for a shape is the total distance around it measured in units. The formula to find the perimeter of a trapezoid is a + b + c + d, where a & b are the bases, and c & d are the lengths of the other sides.

» <u>Solution</u>

Adding up all the sides, we get:

$11+7+4+4$
$18+4+4$
$22+4$
$26$

26 inches

3 0

2 years ago

Charlie has 32 cats, which is 8 times as many cats as Waylon. How many cats does Waylon have?

olya-2409 [2.1K]

You have to do 32 divided by 8

6 0

2 years ago

Read 2 more answers

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0

3 years ago

What is the square root of 73 to the nearest hundredth?

iogann1982 [59]

Sqrt 73 = 8.54 (thats rounded to nearest hundredth)

8 0

3 years ago